Answer:
The tension in the cable when the craft was being lowered to the seafloor is 4700 N.
Explanation:
Given that,
When the craft was stationary, the tension in the cable was 6500 N.
When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N.
The drag force of 1800 N will act in the upward direction. As it was lowered or raised at a steady rate, so its acceleration is 0. As a result, net force is 0. So,
T + F = W
Here, T is tension
F = 1800 N
W = 6500 N
Tension becomes :
So, the tension in the cable when the craft was being lowered to the seafloor is 4700 N.
Answer:
A) θ = 13.1º , B) E
Explanation:
A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.
In this reference system the only force that we must decompose is the Normal one, let's use trigonometry
sin θ = Nₓ / N
cos θ = 
/ N
Nₓ = N sin θ
Ny = N cos θ
x-axis (radial)
Nₓ = m a
where the acceleration is centripetal
a = v² / R
we substitute
-N sin θ = -m v² / R (1)
the negative sign indicates that the force and acceleration towards the center of the circle
y-axis (Vertical)
Ny - W = 0
N cos θ = mg
N = mg / cos θ
we substitute in 1
mg / cos θ sin θ = m v² / R
g tan θ = v² / R
θ = tan⁻¹ (v² / gR)
we calculate
θ = tan⁻¹ (25² / 9.8 274)
θ = 13.1º
B) when comparing the equations the correct one is E
Answer:
A
Explanation:
v = change of X / change of T
v = 200/19.3
A circuit computes various types of Boolean operations. As in the question no specific circuit has been shown,so we have to know the fundamental logic operations.
Out of the various types of logic operations in Boolean algebra,the simple operations are- addition,subtractions,multiplications,division through logic gates.
Various logic or Boolean operations are NOT GATE,OR GATE ,AND GATE .
There are other operations also like NAND GATE,NOR GATE and XOR GATE etc
NOT gate is the simple logic gate which inverts one quantity.it makes 1[high] to 0[low] and vice versa.
OR gate gives 1 [high] when one of the input is 1 and low when all the inputs are low.
AND operation gives 1 when all the inputs are high and low when one of the input is low
NAND operation is AND gate followed by a NOT gate
NOR operation is the OR gate followed by a NOT gate.
Remembering these simple rules we can get the idea of the operations involved in the circuit. Each circuit has different symbols and gives different results.
Answer:
d) v1 = v2 = v3
Explanation:
This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.
At the original point we have, for the three balls:
At the final point we have, for the three balls:
Since we have 
, and 
is the same for all balls, then 
is the same for all balls, which means that 
, the final velocity, is the same for all balls.
