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coldgirl [10]
2 years ago
11

An ideal gas trapped inside a thermally isolated cylinder expands slowly by pushing back against a piston. The temperature of th

e gas
a. decreases.
b. increases.
c. remains the same if the process occurs quickly.
d.remains the same.
e. increases if the process occurs quickly.
Physics
1 answer:
Archy [21]2 years ago
3 0

Answer:

Explanation:idk sry

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FromTheMoon [43]

Answer:

Part a)

Direction of net force is

\theta = 46.7 degree

Part b)

Direction of the velocity is given as

\phi = 27.9 degree

Explanation:

As we know that the velocity of the particle is given as

v = 8.00 t \hat i + 3.00 t^2\hat j

now the acceleration is given as

a = \frac{dv}{dt}

a = 8.00 \hat i + 6.00 t\hat j

now magnitude of net acceleration is given as

a = \sqrt{64 + 36t^2}

F = 3a

35 = 3\sqrt{64 + 36t^2}

t = 1.41 s

Part a)

Now direction of net force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{6t}{8}

tan\theta = \frac{6(1.41)}{8}

\theta = 46.7 degree

Part b)

Direction of the velocity is given as

tan\phi = \frac{v_y}{v_x}

tan\phi = \frac{3.00 t^2}{8.00 t}

tan\phi = \frac{3.00(1.41)}{8.00}

\phi = 27.9 degree

8 0
2 years ago
If the blocks are released from rest, which way does the 10 kg block slide, and what is its acceleration? enter a positive value
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What is the value of the composite constant (gmer2e), to be multiplied by the mass of the object mo in the equation above? expre
Bezzdna [24]

The solution would be like this for this specific problem:

 

 

F = (G Me Mo) / Re^2 

F / Mo = (G Me) / Re^2 

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U = 0, initial vertical velocity

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t = 19.62/9.8 = 2.00 s

Answer:  2.0 s
8 0
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