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djverab [1.8K]
2 years ago
8

Differences between Pressure and upthrust​

Physics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

Answer:

Pressure is equal to the ratio of thrust to the area in contact. Upthrust is a force exerted by the fluids on an object placed in the fluid . Upthrust acts in upward direction.

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Charina says that when waves interact with an object, they will interfere with the object, and that when waves interact with oth
s344n2d4d5 [400]
No, she has it backward.  Waves interfere with each other and reflect off objects.  When two waves overlap their amplitudes add.  If they have the same sign this addition is constructive, meaning the amplitudes grow.  If they have opposite signs this constitutes subtraction and the waves can partially, or completely cancel.  This is known as interference.  Reflection occurs when waves travel from one medium to another.  If the wave impedance of the new medium is different (which it generally is) there will be a partial, or even total, reflection.  
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1 year ago
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Kristina works out seven days a week. Lately, she has been tired, and her body aches. If she is overtraining, which training pri
sertanlavr [38]

Answer: Option (b) is the correct answer.

Explanation:

As Kristina is over training, therefore, there is pain in her muscles because human body also requires rest in order to work or function properly.

That is why, gym trainers suggest to give one day off in a week for your workout sessions so that body muscles should recover.

Thus, we can conclude that if Kristina is over training, then recovery training principle should Kristina consider before continuing her program.

8 0
2 years ago
A long-distance swimmer is able to swim through still water at 4.0 km/h. She wishes to try to swim from Port Angeles, Washington
Roman55 [17]

Let \theta be the direction the swimmer must swim relative to east. Then her velocity relative to the water is

\vec v_{S/W}=\left(4.0\dfrac{\rm km}{\rm h}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)

The current has velocity vector (relative to the Earth)

\vec v_{W/E}=\left(3.0\dfrac{\rm km}{\rm h}\right)\,\vec\imath

The swimmer's resultant velocity (her velocity relative to the Earth) is then

\vec v_{S/E}=\vec v_{S/W}+\vec v_{W/E}

\vec v_{S/E}=\left(\left(4.0\dfrac{\rm km}{\rm h}\right)\cos\theta+3.0\dfrac{\rm km}{\rm h}\right)\,\vec\imath+\left(4.0\dfrac{\rm km}{\rm h}\right)\sin\theta\,\vec\jmath

We want the resultant vector to be pointing straight north, which means its horizontal component must be 0:

\left(4.0\dfrac{\rm km}{\rm h}\right)\cos\theta+3.0\dfrac{\rm km}{\rm h}=0\implies\cos\theta=-\dfrac{3.0}{4.0}\implies\theta\approx138.59^\circ

which is approximately 41º west of north.

6 0
2 years ago
ANSWER BELOW QUESTIONS:
Bogdan [553]

Answer:

why should we do , do by your own , no sense

Explanation:

3 0
2 years ago
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A rescue helicopter wants to drop a package of supplies to isolated mountain climbers on a rocky ridge 200 m below. If the helic
andreev551 [17]

Answer:

a) 447.21m

b) -62.99 m/s

c)94.17 m/s

Explanation:

This situation we can divide in 2 parts:

⇒ Vertical : y =-200 m

y =1/2 at²

-200 = 1/2 *(-9.81)*t²

t= 6.388766 s

⇒Horizontal: Vx = Δx/Δt

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b) ⇒ Horizontal

Vx = Δx/Δt ⇒ 70 = 400 /Δt

Δt= 5.7142857 s

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y = v0t + 1/2 at²

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v= v0 +at

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v= -62.99 m/s

c) √(70² + 62.99²) = 94.17 m/s

8 0
2 years ago
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