A glider of mass 0.240 kg is on a frictionless, horizontal track, attached to a horizontal spring of force constant 6.00 N/m. In
1 answer:
Answer:
.
Explanation:
The mechanical energy of the system will be the kinetic energy plus the elastic potential energy: .
We know that the equation for the kinetic energy is , where <em>m </em>is the mass of the object and <em>v </em>its velocity.
We know that the equation for the elastic potential energy is , where <em>k</em> is the spring constant and
the compression (or elongation) respect to equilibrium.
So for our values we have:
.
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Answer:
(we need the mass of the astronaut A)
Explanation:
We can solve this by using the conservation law of the linear momentum P. First we need to represent every mass as a particle. Also we can simplify this system of particles by considering only the astronaut A with an initial speed of 0 m/s and a mass
and the IMAX camera with an initial speed
of 7.5 m/s and a mass
of 15.0 kg.
The law of conservation says that the linear momentum P (the sum of the products between all masses and its speeds) is constant in time. The equation for this is:
By the law of conservation we know that
For (final linear momentum) we need to treat the collision as a plastic one (the two particles stick together after the encounter).
So:
Answer:
(a). The initial velocity is 28.58m/s
(b). The speed when touching the ground is 33.3m/s.
Explanation:
The equations governing the position of the projectile are
where is the initial velocity.
(a).
When the projectile hits the 50m mark, ; therefore,
solving for we get:
Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that
which gives
(b).
The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,
the vertical component of the velocity is
which gives a speed of