Drying of Cassava (Tapioca) Root. Tapioca flour is used in many countries for bread and similar products. The flour is made by d
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Answer: Volume of Freon = 12.23.L
Explanation: First, the temperatures have to be in the same unit, so all the tmeperatures is transformed into Kelvin:
T₁ = 192K
T₂ = . (F - 32)+273.15
T₂ = . (- 65 - 32)+273.15
T₂ = 219.26K.
Second, BTU is an unit of energy. It can be transformed into Joules by the relation 1BTU = 1055.06J.
Q = 1055.06 . 46.9 = 49482.314J
The letter Q represents Heat and is calculated as Q = m.Cp.ΔT, where:
m is mass of the element;
Cp is the heat capacity specific for each element;
ΔT is the difference between the final and initial temperature;
Third, it will be needed the properties of the Freon:
Freon (CF2Cl2) = 120.91g/mol; Cp = 74J/mol.K; ρ = 1.49kg/m³
Fourth, we calculate the mass of Freon necessary for the remove of 46.9BTU of energy from the system:
Q = m.Cp.ΔT
m=
m =
m = 18228.214g or m=18.228Kg
Fifth, using the density of Freon, Volume can be found
ρ =
V = m / ρ
V = 18.228 / 1.49
V = 12.23m³
As SI for density is Kg/m³, the volume found is in m³.
Cubic meters is related to Liters as the following: 1m³=1000l.
So, volume of Freon = 12.23.L
The volume of Freon needed is 12.23.L.
Answer:
3433.5 N
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
m = Mass of person = 70 kg
According to the question
a = Acceleration
Balancing the forces we have
The required force is 3433.5 N
Answer:
See the explanation below.
Explanation:
12) When an object is falling, how does the objects velocity change? what formula do you use?
The speed of a falling object is increased by a value of 9.81 meters per second per second. That is if we throw any body regardless of mass from a considerable height, its speed in the first second will be 9.81[ m/ s] , in the next second will be equal to 19.62 [m/s] in the next will be equal to 29.43 [m/ s].
The formula is:
where:
vo = initial velocity = 0
g = gravity = 9.81[m/s^2]
t = time [s]
13)
what is a falling speed at 6s, 9s, 112s?
v = 0 + (9.81*6) = 58.86[m/s]
v = 0 + (9.81*9) = 88.29 [m/s]
v = 0 + (9*112) = 1098.72 [m/s]
14)
If an object is falling at 65 [m/s]. How long has it been falling ? what is the formula that you use?
The formula is the same:
65 = 0 + 9.81*t
t = 65/9.81
t = 6.62[s]
15)
What formula is used to determine the distance an object is falling ?
where:
y = distance [m]
yo = initial distance, in most of the cases and depending of the reference point it will be eqaul to zero
vo = initial velocity, if it is free fall, then = 0
t = time [s]
g = gravity = 9.81[m/s^2]
This equation will be reduce to:
16)
using the times given in problem 13. Determine the distance fallen for each.
y = 0.5*9,81*(6)^2 = 176.58 [m]
y = 0.5*9,81*(9)^2 = 397.3 [m]
y = 0.5*9,81*(112)^2 = 61528.3 [m]
17)
If an object has fallen a distance of 87.3 [m]. How long was it falling?
87.3 = 0.5*9.81*t^2