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Sedbober [7]
1 year ago
7

A student is collecting the gas given off from a plant in bright sunlight at a temperature of 27°c. The gas being collected is p

robably
Physics
1 answer:
Brums [2.3K]1 year ago
4 0

Answer: The gas being collected is probably Oxygen

Explanation:

Plants produce oxygen through a process known as photosynthesis by utilizing carbon monoxide, a by-product produced by humans during the process of breathing. Humans also breathe in the oxygen ( by-product of photosynthesis) produced by the plants. Therefore, humans and plants live in a symbiotic relationship.

Photosynthesis is the process plants use to synthesize food from carbon dioxide and water. Sunlight is used as a energy source. Photosynthesis releases oxygen as a byproduct.

At low temperatures, between 0 and 10 degrees Celsius – the enzymes that carry out photosynthesis do not work efficiently, and this decreases the photosynthetic rate.

At medium temperature above 10 degrees Celsius to below 40 degrees Celsius (e.g 27 degrees Celsius), the photosynthetic enzymes work at their optimum levels, so photosynthesis proceeds.

At a temperature above 40 degrees Celsius, the enzymes that carry out photosynthesis lose their shape and functionality, and the photosynthetic rate declines rapidly.

Equation for photosynthesis reaction:

6CO2 + 6H20 + (energy) = C6H12O6 + 6O2

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Every winter I fly home to Chicago. It takes 3 hours. What is my average speed?
Tanya [424]

It depends on where you live when you're not visiting Chicago. We need to know the distance of the trip.

Your average speed on the trip is . . .

(total distance in miles) / (3 hours)

miles per hour

5 0
1 year ago
one horsepower is a unit of power equal to 746w. how much energy can a 150-horsepower engine transform in 10.0s?
Dafna1 [17]

1 watt = 1 joule/second

1 horsepower = 746 watts = 746 joule/second

   (150 horsepower) x (746 watt/HP) x (1 joule/sec  /  watt) x (10 sec)

=  (150 x 746 x 1 x 10)  joule  =  1,119,000 joules .   
if correct plz mark brainly
8 0
1 year ago
The current in a long solenoid of radius 6 cm and 17 turns/cm is varied with time at a rate of 5 A/s. A circular loop of wire of
jonny [76]

Answer:

53.63 μA

Explanation:

radius of solenoid, r = 6 cm

Area of solenoid = 3.14 x 6 x 6 = 113.04 cm^2 = 0.0113 m^2

n = 17 turns / cm = 1700 /m

di / dt = 5 A/s

The magnetic field due to the solenoid is given by

B = μ0 n i

dB / dt = μ0 n di / dt

The rate of change in magnetic flux linked with the solenoid =

Area  of coil x dB/dt

= 3.14 x 8 x 8 x 10^-4 x μ0 n di / dt

= 3.14 x 64 x 10^-4 x 4 x 3.14 x 10^-7 x 1700 x 5 = 2.145 x 10^-4

The induced emf is given by the rate of change in magnetic flux linked with the coil.

e = 2.145 x 10^-4 V

i = e / R = 2.145 x 10^-4 / 4 = 5.36 x 10^-5 A = 53.63 μA

6 0
1 year ago
The diagram shows the electric field around two charged objects. What is the best conclusion about the charges that can be made
Lemur [1.5K]

The Correct answer is (B), Because the reject each other.

8 0
2 years ago
Read 2 more answers
A spaceship of mass 8600 kg is returning to Earth with its engine turned off. Consider only the gravitational field of Earth. Le
Katyanochek1 [597]

Answer:

\Delta KE = 4.20\times 10^{13}\ J

Explanation:

given,

mass of spaceship(m) = 8600 Kg

Mass of earth = 5.972 x 10²⁴ Kg

position of movement of space ship

R₁ = 7300 Km

R₂ = 6700 Km

the kinetic energy of the spaceship increases by = ?

Increase in Kinetic energy = decrease in potential energy

    \Delta KE = GMm (\dfrac{1}{R_2}-\dfrac{1}{R_1})

    \Delta KE = GMm (\dfrac{R_1-R_2}{R_2R_1})

    \Delta KE = 6.67 \times 10^{-11}\times 5.972 \times 10^{24}\times 8600 (\dfrac{7300 - 6700}{7300 \times 6700})

    \Delta KE = 6.67 \times 10^{-11}\times 5.972 \times 10^{24}\times 8600 (\dfrac{600}{48910000})

    \Delta KE = 4.20\times 10^{13}\ J

5 0
1 year ago
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