Answer:
The density of the mercury is 13.2 g/cm³
Explanation:
Density is a measurement that compares the amount of matter an object
has to its volume
Density is equal to mass divided by volume
We need to find the density of mercury if 500 cm³ has a mass of
6.60 kg in g/cm
We must to change The kilogram to grams
The mass of mercury is 6.60 kilograms
1 kilogram = 1000 grams
6.60 kilograms = 6.60 × 1000 = 6600 grams
Density = mass ÷ volume
The volume of the mercury is 500 cm³
The density = 6600 ÷ 500
The density = 13.2 g/cm³
<em>The density of the mercury is 13.2 g/cm³ </em>
We need a and we have m and F . Now a = f÷m so therefore a = 4,9 ÷ 0,5 which is 0,98 metres per cubic second
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The magnitude is
, the direction is into the page
Explanation:
From the question we are told that
The current is 
The radius of arc bc is 
The radius of arc da is 
The length of segment cd and ab is = 
The objective of the solution is to obtain the magnetic field
Generally magnetic due to the current flowing in the arc is mathematically represented as
Here I is the current
is the permeability of free space with a value of 
r is the distance
Considering Arc da

Where
is the angle the arc da makes with the center from the diagram its value is 
Now substituting values into formula for magnetic field for da
![B_{da} = \frac{4\p *10^{-7} * 12}{4 \pi (0.20)}[\frac{2 \pi}{3} ]](https://tex.z-dn.net/?f=B_%7Bda%7D%20%3D%20%5Cfrac%7B4%5Cp%20%2A10%5E%7B-7%7D%20%2A%2012%7D%7B4%20%5Cpi%20%280.20%29%7D%5B%5Cfrac%7B2%20%5Cpi%7D%7B3%7D%20%5D)
![= \frac{10^{-7} * 12}{0.20} * [\frac{2 \pi}{3} ]](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B10%5E%7B-7%7D%20%2A%2012%7D%7B0.20%7D%20%2A%20%5B%5Cfrac%7B2%20%5Cpi%7D%7B3%7D%20%5D)

Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to da is into the pages of the paper
Considering Arc bc

Substituting value
![B_{bc} = \frac{4 \pi *10^{-7} * 12}{4 \pi (0.30)} [\frac{2 \pi}{3} ]](https://tex.z-dn.net/?f=B_%7Bbc%7D%20%3D%20%5Cfrac%7B4%20%5Cpi%20%2A10%5E%7B-7%7D%20%2A%2012%7D%7B4%20%5Cpi%20%280.30%29%7D%20%5B%5Cfrac%7B2%20%5Cpi%7D%7B3%7D%20%5D)

Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to bc is out of the pages of the paper
Since the line joining P to segment bc and da makes angle = 0°
Then the net magnetic field would be



Since
then the direction of the net charge would be into the page
Answer:
On a velocity-time graph… slope is acceleration. the "y" intercept is the initial velocity. when two curves coincide, the two objects have the same velocity at that time.