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brilliants [131]
2 years ago
8

What do slinky waves and seismic waves have in common? A. They both always occur as transverse waves. B. They both always occur

as longitudinal waves. C. Both are electromagnetic waves. D. Both exhibit the same particle-to-particle interaction. E. Both are mechanical waves.
Physics
2 answers:
anyanavicka [17]2 years ago
8 0

Answer:

E> Both are Mechanical waves

Explanation:

As we know that Slinky waves are transverse in nature and medium particles will move to and fro while wave propagate through the medium.

While Seismic waves are of two type

(i) P waves   (ii) S Waves

these both moves in form of compression and rarefaction and it can travel through the medium.

So here in case of Seismic wave we can say it is longitudinal waves.

So here we can say that they both have common that they both requires medium to move from one end to other end.

So they both are mechanical waves

Usimov [2.4K]2 years ago
3 0

the answer is E both are mechanical waves

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Which describes a grizzly bear’s habitat? all the biotic factors in the ecosystem all the abiotic factors in the ecosystem the r
Talja [164]

Answer:

I found this question elsewhere on brainly and the answer was verified. Here it is!

Explanation:

Grizzly bear habitats is the habitat or the physical space where the bear lives. Grizzly bears can be found in many different habitats from dense forests to subalpine meadows, arctic tundra and open plains. We can also conclude that all of the bears live in grizzly bear's habitat in order to survive.

3 0
2 years ago
Read 2 more answers
d. The force is doubled and the object’s mass is halved? 18. ||| A man pulling an empty wagon causes it to accelerate at 1.4 m/s
Harrizon [31]

Answer:

a' = 0.35 m/s^2

Explanation:

Let say the empty wagon has mass "M"

now by newton's II Law we will have

F = Ma

now it is given that empty wagon is pulled with acceleration 1.4 m/s/s

now we will have

F = 1.4 M

now a child of mass three times the mass of wagon is sitting on the empty wagon

so here we have

F = (M + 3M) a

1.4 M = 4M a'

so we have

a' = 0.35 m/s^2

8 0
2 years ago
A hydraulic press has one piston of diameter 2.0 cm and the other piston of diameter 16.0 cm. What force must be applied to the
SVETLANKA909090 [29]

Answer:

<em>The force applied to the smaller piston = 2512 N</em>

Explanation:

Hydraulic press:  A hydraulic press is a device used to produce a very large force. A hydraulic force operates based on pascal's principle.

F/f = A/a................ Equation 1

making f the subject of the equation above

f =(F×a)/A............. Equation 2

Where F = Force on the larger piston, f = force on the smaller piston, A = area of the larger piston, a = area of the smaller piston.

<em>Given: F = 3200 N,  and</em>

<em>Area (A) = πD²/4 where D = 16.0 cm = 0.16 m</em>

<em>A = 3.143×(0.16)²/4 = 0.02 m²</em>

<em>Also</em>

<em>a = πd²/4 where d = 2 cm = 0.02 cm</em>

<em>a = 3.143×(0.02)²/4</em>

<em>a = 0.0157 m²</em>

<em>Substituting these values into equation 2</em>

<em>f = (3200×0.0157)/0.02</em>

<em>f = 2512 N</em>

<em>The force applied to the smaller piston = 2512 N</em>

5 0
2 years ago
A car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. The average acceleration of the c
Gwar [14]
The acceleration is the change of speed/velocity over time. Thus to calculate this you do (V1-V2)/T or (11.2-9.6)/4 or 0.4 m/s^2
5 0
1 year ago
Read 2 more answers
Charge is flowing through a conductor at the rate of 420 C/min. If 742 J. of electrical energy are converted to heat in 30 s., w
Y_Kistochka [10]

Answer:

3.53 V

Explanation:

Electric charge: The is the rate of flow of electric charge along a conductor.

The S.I unit of electric charge is C.

Mathematically it is expressed as,

Q = It ............................ Equation 1

Where Q = electric charge, I = current, t = time.

I = Q/t.......................... Equation 2

From the question, charge flows through the conductor at the rate of 420 C/mim

Which means in 1 min, 420 C of charge flows through the conductor.

Hence,

Q = 420 C, t = 1 min = 60 seconds

Substitute into equation 2

I = 420/60

I =7 A

Also

P = VI......................... Equation 3

Where P = power, V = potential drop, I = current.

V = P/I................... Equation 4

Note: Power = Energy/time

From the question, P = 742/30 = 24.733 W. and I = 7 A.

Substitute these values into equation 4

V = 24.733/7

V = 3.53 V

Hence the potential drop across the conductor =  3.53 V

4 0
2 years ago
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