If you use the next formula with the data given in the exercise you are asking:
Ey[3.4] - F[1.7] = 0
<span>Ey = F/2
</span>and after that what you need to do is sum the moments of the handle about D to zero asumming it is a positive moment and we proceed like this
Ey[1.5sin19] – P[21 – 1.5sin19] = 0
<span>(F/2)[1.5sin19] = P[21 – 1.5sin19] </span>
<span>F = 2P[21 – 1.5sin19] / [1.5sin19] </span>
<span>F = 84P </span>
A sound wave. Because in a vacuum there is no medium in a vacuum. And the only wave that requires a medium to travel through is a sound wave.
Answer:3.95 m/s
Explanation:
Given
mass of object 
radius of circle 
initial Position 
angular displacement 
8.95 radian can be written as
i.e. Particle is at first quadrant with 
(c)velocity is 
Answer:
Note: Angular momentum is always conserved in a collision.
The initial angular momentum of the system is
L = ( It ) ( ωi )
where It = moment of inertia of the rotating circular disc,
ωi = angular velocity of the rotating circular disc
The final angular momentum is
L = ( It + Ir ) ( ωf )
where ωf is the final angular velocity of the system.
Since the two angular momenta are equal, we see that
( It ) ( ωi ) = ( It + Ir ) ( ωf )
so making ωf the subject of the formula
ωf = [ ( It ) / ( It + Ir ) ] ωi
Explanation:
Here in this question as we can see there is no air friction so we can use the principle of energy conservation
now here we know that
now plug in all values in above equation
divide whole equation by mass "m"
so height of the ball from ground will be 1.35 m
