answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bingel [31]
2 years ago
11

A set of data is collected for object in an inelastic collision, as recorded in the table.

Physics
1 answer:
TiliK225 [7]2 years ago
5 0

Answer:

To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.

Object 1 has momentum of 8 kg. m/s before collision.

Object 1 has momentum of 0 kg. m/s before collision.

The combined mass after the collision had a total momentum of 8 kg. m/s.

Explanation:

Momentum of the object is given by,

Momentum = mass × velocity

For object 1:

Momentum = mass × velocity

Momentum = 2 × 4

Momentum = 8 kg. m/s

For object 2:

Momentum = mass × velocity

Momentum = 6 × 0

Momentum = 0 kg. m/s

For object 1 + object 2:

Momentum = mass × velocity

Momentum = 8 × 1

Momentum = 8 kg. m/s

To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.

Object 1 has momentum of 8 kg. m/s before collision.

Object 1 has momentum of 0 kg. m/s before collision.

The combined mass after the collision had a total momentum of 8 kg. m/s.


You might be interested in
The density of aluminum is 2.7 × 103 kg/m3 . the speed of longitudinal waves in an aluminum rod is measured to be 5.1 × 103 m/s.
andrey2020 [161]
<span>The speed of longitudinal waves, S, in a thin rod = âšYoung modulus / density , where Y is in N/m^2. So, S = âšYoung modulus/ density. Squaring both sides, we have, S^2 = Young Modulus/ density. So, Young Modulus = S^2 * density; where S is the speed of the longitudinal wave. Then Substiting into the eqn we have (5.1 *10^3)^2 * 2.7 * 10^3 = 26.01 * 10^6 * 2.7 *10^6 = 26.01 * 2.7 * 10^ (6+3) = 70.227 * 10 ^9</span>
5 0
2 years ago
What’s 2.3 miles into kilometers
True [87]
3.701 kilometers hope that helps
8 0
2 years ago
A point charge q1 = 4.50 nC is located on the x-axis at x = 1.95 m , and a second point charge q2 = -6.80 nC is on the y-axis at
Vinvika [58]

Answer:

Explanation:

One charge is situated at x = 1.95 m . Second charge is situated at y = 1.00 m

These two charges are situated outside sphere as it has radius of .365 m with center at origin. So charge inside sphere = zero.

Applying Gauss's theorem

Flux through spherical surface = charge inside sphere / ε₀

= 0 / ε₀

= 0 Ans .

3 0
2 years ago
The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t , where the time tis in seconds. The
Reika [66]

Complete question:

The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The

particle is momentarily at rest at t is:

Select one:

a. 9.3s

b. 1.3s

C. 0.75s

d.5.3s

e. 7.3s

​

Answer:

b. 1.3 s

Explanation:

Given;

position of the particle, x(t)=1 6t- 3.0t³

when the particle is at rest, the velocity is zero.

velocity = dx/dt

dx /dt = 16 - 9t²

16 - 9t² = 0

9t² = 16

t² = 16 /9

t = √(16 / 9)

t = 4/3

t = 1.3 s

Therefore, the particle is momentarily at rest at t = 1.3 s

6 0
2 years ago
A material that has a fracture toughness of 33 MPa.m0.5 is to be made into a large panel that is 2000 mm long by 250 mm wide and
scoray [572]

Answer:

F_{allow} = 208.15kN

Explanation:

The word 'nun' for thickness, I will interpret in international units, that is, mm.

We will begin by defining the intensity factor for the steel through the relationship between the safety factor and the fracture resistance of the panel.

The equation is,

K_{allow} =\frac{K_c}{N}

We know that K_c is 33Mpa*m^{0.5} and our Safety factor is 2,

K_{allow} = \frac{33Mpa*m^{0.5}}{2} = 16.5MPa.m^{0.5}

Now we will need to find the average width of both the crack and the panel, these values are found by multiplying the measured values given by 1/2

<em>For the crack;</em>

\alpha = 0.5*L_c = 0.5*4mm = 2mm

<em>For the panel</em>

\gamma = 0.5*W = 0.5*250mm = 125mm

To find now the goemetry factor we need to use this equation

\beta = \sqrt{sec(\frac{\pi\alpha}{2\gamma})}\\\beta = \sqrt{sec(\frac{2\pi}{2*125mm})}\\\beta = 1

That allow us to determine the allowable nominal stress,

\sigma_{allow} = \frac{K_{allow}}{\beta \sqrt{\pi\alpha}}

\sigma_{allow} = \frac{16.5}{1*\sqrt{2*10^{-3} \pi}}

\sigma_{allow} = 208.15Mpa

So to get the force we need only to apply the equation of Force, where

F_{allow}=\sigma_{allow}*L_c*W

F_{allow} = 208.15*250*4

F_{allow} = 208.15kN

That is the maximum tensile load before a catastrophic failure.

4 0
2 years ago
Other questions:
  • The voltage entering a transformer’s primary winding is 120 volts. The primary winding is wrapped around the iron core 10 times.
    13·2 answers
  • A 4.0 Ω resistor, an 8.0 Ω resistor, and a 12.0 Ω resistor are connected in parallel across a 24.0 V battery. What is the equiva
    14·2 answers
  • A cyclist moving towards right with an acceleration of 4m/s² at t = 0 he has travelled 5 m moving towards the right at 15 m/s wh
    7·1 answer
  • How do some businesses believe VR is affecting their training for employees?
    5·1 answer
  • A box sliding on a horizontal frictionless surface encounters a spring attached to a rigid wall and compresses the spring by a c
    9·1 answer
  • A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the
    15·1 answer
  • Spacecraft have been sent to Mars in recent years. Mars is smaller than Earth and has correspondingly weaker surface gravity. On
    7·1 answer
  • A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of rocks, which doubles its mass, and leaves at
    5·1 answer
  • Calculate the work WC done by the gas during the isothermal expansion. Express WC in terms of p0, V0, and Rv.
    12·1 answer
  • Use the idea of density to explain why the dead creatures sink to the seabed​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!