Answer:
Both of the stunt professionals will sustain injuries of the same seriousness
Explanation:
We are being told that both stunt professionals are standing from the same height, therefore they will attain the same equivalent speed at the bottom if we are to look at it from the principle of conservation of energy.
Now; According to principle of momentum; the momentum at which the first stunt professional A hits the ground be equal as the momentum with which stunt professional B will hit the wall.
Thus; both of the stunt professionals will sustain injuries of the same seriousness
B. A 50g fish swimming in a fish tank.
Answer:
From the initial height h
Explanation:
When a material or substance is drop from a height h, it possesses potential energy, immediately it is dropped from that height, the potential energy is gradually converted to kinetic energy, it gets to a point where the potential energy equals the kinetic energy, as the material touches the ground, all potential energy has been converted to kinetic energy already
Answer:
Explanation:
Given that,
Spring constant = 16N/m
Extension of spring
x = 8cm = 0.08m
Mass
m = 5g =5/1000 = 0.005 kg
The ball will leave with a speed that makes its kinetic energy equal to the potential energy of the compressed spring.
So, Using conservation of energy
Energy in spring is converted to kinectic energy
So, Ux = K.E
Ux = ½ kx²
Then,
Ux = ½ × 16 × 0.08m²
Ux = 0.64 J
Since, K.E = Ux
K.E = 0.64 J
F= (speed)/(wavelength)
Therefore, speed = Frequency x wavelength
V = 68m/s
