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elixir [45]
2 years ago
7

The charges for four ions are sodium (Na) +1, calcium (Ca) +2, fluorine (F) –1, and sulfur (S) –2. Which would be an ionic bond

that could form from any of these ions?
A.NaCa2
B.Na2S
C.CaF
D.FS

Physics
2 answers:
FromTheMoon [43]2 years ago
7 0

Answer: B. Na_2S

Explanation: An ionic bond is formed when an element completely transfers its valence electron to another element. Ionic bond is formed between a metal and an non-metal.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here Na is having an oxidation state of +1 and sulfur has an oxidation state of -2. Thus they combine to form neutral Na_2S.

Ca is having an oxidation state of +2 and fluorine has an oxidation state of -1. Thus they combine to form neutral CaF_2. and not CaF.

Ludmilka [50]2 years ago
3 0
The correct answer would be B. It is the compound Na2S that forms an ionic bond from the given ion above. From the choices, it is the only compound that exist and is available. Metals cannot react with another metal as well as nonmetal to nonmetal. 
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Answer:

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Kasaysayan ng PilipinasAng Pilipinas ay isang bansa na makikita sa timog-silangang Asya at malapit sa dagat Pasipiko. Ito ay binubuo ng mahigit sa 7000 na isla, at nagsisilbing tirahan para sa mga Pilipino. Ang mga sumusunod ay ilan lamang sa mga paraan kung paanong nakatulong ang estratehikong lokasyon ng ating bansa sa pagbuo ng ating kasaysayan:Dahil tayo ay napalilibutan ng anyong tubig, pangingisda ang naging pangunahing pamumuhay ng mga sinaunang Pilipino.

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A metal disk weighing 1 N is resting on an index card that is balanced on top of a glass. When the index card is quickly pulled
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Step by step explanation:
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An object of mass 24kg is accelerated up a frictionless place incline at an angle of 37° with horizontal by a constant force, st
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a) Average power: 1425 W

b) Instantaneous power at 3.0 sec: 2850 W

Explanation:

a)

The motion of the object along the ramp is a uniformly accelerated motion (because the force applied is constant), so we can use the suvat equation

s=ut+\frac{1}{2}at^2

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s = 18 m is the displacement along the ramp

u = 0 is the initial velocity

t = 3.0 s is the time taken

a is the acceleration of the object along the ramp

Solving for a,

a=\frac{2s}{t^2}=\frac{2(18)}{(3.0)^2}=4 m/s^2

Now we can apply Newton's second law to find the net force on the object:

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This net force is the resultant of the applied force forward (F_a) and the component of the weight acting backward (mg sin \theta), so we can find what is the applied force:

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where

m = 24 kg is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

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where s = 18 m is the displacement.

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P=\frac{W}{t}=\frac{4276}{3}=1425 W

b)

The instantaneous power at any point of the motion is given by

P=F_av

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F_a=237.5 N

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From which we find
\theta_r = \arcsin (0.288)=16.7^{\circ}
6 0
2 years ago
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