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STALIN [3.7K]
2 years ago
9

Points A, B, and C form the vertices of a triangle in a nonuniform electrostatic field. The electrostatic work done on a particl

e of charge q as the particle travels from A to B is WAB and that done on the particle as it travels from A to C is WAC=−WAB/3.
a) How much electrostatic work is done on the particle as it travels from B to C?
Physics
1 answer:
Trava [24]2 years ago
4 0

Answer:

Explanation:

Let electric potential at A ,B and C be Va , Vb and Vc respectively.

Work done = charge x potential difference

Wab = q ( Va - Vb )

Wac =  q (  Va -  Vc )

Given

Wac = - Wab / 3

3Wac = - Wab

Now

Wbc = q ( Vb - Vc )

= q [ ( Va-Vc ) - ( Va - Vb )]  

= Wac - Wab

= Wac + 3Wac

= 4Wac

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A charge of uniform volume density (40 nC/m3) fills a cube with 8.0-cm edges. What is the total electric flux through the surfac
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Answer:

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Edge of the cube, a = 8.0 cm = 8.0\times 10^{- 2}\ m

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To calculate the electric flux:

\phi = \frac{q}{\epsilon_{o}}                                                      (1)

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\epsilon_{o} = 8.85\times 10^{- 12}\ F/m = permittivity of free space  

Volume Charge density for the given case is given by the formula:

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