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mina [271]
2 years ago
11

Olivia wants to find out whether a substance will fluoresce. She says she should put it in a microwave oven. Do you agree with h

er? Why or why not?
Physics
2 answers:
Luda [366]2 years ago
3 0

Disagree

Explanation:

Fluoresce objects will glow when put under Ultraviolet light as the molecules are excited by the ultraviolet radiation.

Microwaves give micro-waves that are present in another spectrum of wave length and will not be able to fluoresce the molecules

Schach [20]2 years ago
3 0
<span>I disagree with her because many substances show fluorescence under ultraviolet light, not microwaves. </span>
You might be interested in
A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
dlinn [17]

Answer:

a = 4.72 m/s²  

Explanation:

given,

mass of the box (m)= 6 Kg

angle of inclination (θ) = 39°

coefficient of kinetic friction (μ) = 0.19

magnitude of acceleration = ?

box is sliding downward so,

F - f = m a                        

f is the friction force

m g sinθ - μ N = ma                        

m g sinθ - μ m g cos θ = ma            

a = g sinθ - μ g cos θ                    

a = 9.8 x sin 39° - 0.19 x 9.8 x cos 39°

a = 4.72 m/s²                                      

the magnitude of acceleration of the box down the slope is a = 4.72 m/s²  

3 0
2 years ago
Explain why the brakes of a car get much hotter than the brakes of a bicycle?
ValentinkaMS [17]

Answer: Car brakes produces more energy then the bicycle because the cars wheels produces a much bigger force that makes the car go and to stop that force the car uses greater amount of energy that transfers to heat  but in a bicycle the wheels do not turn that fast so when you press the break there is less energy that transfer to heat.

Explanation:

8 0
2 years ago
A slender uniform rod 100.00 cm long is used as a meter stick. Two parallel axes that are perpendicular to the rod are considere
Nataliya [291]

Answer:

The correct answer is D    I_{30} /I_{50} =   1.5

Explanation:

In this exercise the moment of inertia equation should be used

    I = ∫ r² dm

In addition to the parallel axis theorem

    I = I_{cm} + M D²

Where  I_{cm} is the moment of the center of mass, M is the total mass of the body and D the distance from this point to the axis of interest

Let's apply these relationships to our problem, the center of mass of a uniform rod coincides with its geometric center, in this case the rod is 1 m long, so the center of mass is in

    L = 100.00 cm (1m / 100 cm) = 1.0000 m

     x_{cm} = 50 cm = 0.50 m

Let's calculate the moment of inertia for this point, suppose the rod is on the x-axis and use the concept of linear density

    λ = M / L = dm / dx

    dm =  λ dx

Let's replace in the moment of inertia equation

    I = ∫ x² ( λ dx)

We integrate

    I =  λ x³ / 3

We evaluate between the lower limits x = -L/2 to the upper limit x = L/2

    I =  λ/3 [(L/2)³ - (-L/2)³] = lam/3  [L³/8 - (-L³ / 8)]

    I =  λ/3  L³/4

    I = 1/12  λ L³

Let's replace the linear density with its value

    I = 1/12  (M/L)  L³

    I = 1/12  M L²

Let's calculate with the given values

   I = 1/12  M 1²

   I = 1/12 M

This point is the center of mass of the rod

    Icm = I = 1/12 M  = 8.333 10-2 M

Now let's use the parallel axis theorem to calculate the moment of resection of the new axis, which is 0.30 m from one end, in this case the distance is

    D = x_{cm} - x

    D = 0.50 - 0.30

    D = 0.20  m

Let's calculate

   I_{30} =I_{cm} + M D²

   I_{30} = 1/12 M + M 0.202

   I_{30} = M (1/12 + 0.04)

   I_{30} = M 0.123

To find the relationship between the two moments of inertia, divide the quantities

  I_{30} / I_{50} = M 0.123 / (M 8.3 10-2)

   I_{30} /I_{50} = 1.48

The correct answer is d 1.5

6 0
2 years ago
A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar
finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

\displaystyle V=k\frac{Q}{r}

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

d=\sqrt2 a

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}

\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

The total potential is  

V_t=V_1+V_2+V_3+V_4

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

6 0
2 years ago
When you float an ice cube in water, you notice that 90% of it is submerged beneath the surface. Now suppose you put the same ic
Temka [501]

Answer:

The variation is inversely proportional to the decrease density

Explanation:

This is an exercise where we will use the Archimedes principle that states that the thrust is equal to the weight of the dislodged liquid

         B = m g

         ρf = m / Vf

         m = ρf Vf

         B = ρf Vf g

If we use Newton's second law for equilibrium

          B - W = 0

          B = m g

          ρ Vf g = ρb Vb g

          ρb / ρf = Vf / Vb               (1)

Let's apply this expression to our case

In water

           Vf / Vg = 0.90

replace in equation 1

           ρb / ρf = 0.90

           ρb = ρf 0.90

           ρb = 1000 0.90

           ρb = 900 kg / m3

Now we change the liquid to one with lower density, let's calculate the volume ratio

           Vf / Vg = ρb / ρf

The density of the body (ρb) remains constant if the density of the fluid decreases, as in the denominator the volume fraction increases, whereby the submerged part decreases

The variation is inversely proportional to the decrease density

4 0
2 years ago
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