Answer:
since brick is heavy than feather so at that time air resistance on brick will be more than the air resistance on feather
Explanation:
When an object will reach at its terminal velocity then the acceleration of that object will become ZERO
So at that moment of time we can say that net force on the object must be zero or the force of gravity due to its weight is counter balanced by air friction on the object
So when brick will reach to its terminal speed then we have
when feather will reach to its terminal speed
so here we can say that since brick is heavy than feather so at that time air resistance on brick will be more than the air resistance on feather
Answer:
Explanation:
Here we know that the glider is accelerated uniformly from rest to final speed of 25.7 m/s in total distance of d = 46.9 m
so we will have
d = 46.9
so for uniformly accelerated motion we have
now we will find the total work done given as change in kinetic energy
now power is given as
(a) Greater
The frequency of the nth-harmonic on a string is an integer multiple of the fundamental frequency, :
So we have:
- On wire A, the second-harmonic has frequency of , so the fundamental frequency is:
- On wire B, the third-harmonic has frequency of , so the fundamental frequency is
So, the fundamental frequency of wire A is greater than the fundamental frequency of wire B.
(b)
For standing waves on a string, the fundamental frequency is given by the formula:
where
v is the speed at which the waves travel back and forth on the wire
L is the length of the string
(c) Greater speed on wire A
We can solve the formula of the fundamental frequency for v, the speed of the wave:
We know that the two wires have same length L. For wire A, , while for wave B,
, so we can write the ratio between the speeds of the waves in the two wires:
So, the waves travel faster on wire A.
Answer:
<h2>187,500N/m</h2>Explanation:
From the question, the kinectic energy of the train will be equal to the energy stored in the spring.
Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².
Equating both we will have;
1/2 mv² = 1/2ke²
mv² = ke²
m is the mass of the train
v is the velocity of then train
k is the spring constant
e is the extension caused by the spring.
Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m
Substituting this values into the formula will give;
30000*4² = k*1.6²
The value of the spring constant is 187,500N/m