A brick and a feather fall to the earth at their respective terminal velocities. which object experiences the greater force of a
2 answers:
Answer:
since brick is heavy than feather so at that time air resistance on brick will be more than the air resistance on feather
Explanation:
When an object will reach at its terminal velocity then the acceleration of that object will become ZERO
So at that moment of time we can say that net force on the object must be zero or the force of gravity due to its weight is counter balanced by air friction on the object
So when brick will reach to its terminal speed then we have
when feather will reach to its terminal speed
so here we can say that since brick is heavy than feather so at that time air resistance on brick will be more than the air resistance on feather
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Answer:
circuit sketched in first attached image.
Second attached image is for calculating the equivalent output resistance
Explanation:
For calculating the output voltage with regarding the first image.
For the calculus of the equivalent output resistance we apply thevenin, the voltage source is short and current sources are open circuit, resulting in the second image.
so.
Taking into account the %5 tolerance, with the minimal bound for Voltage and resistance.
if the -5% is applied to both resistors the Voltage is still 5V because the quotient has 5% / 5% so it cancels. to be more logic it applies the 5% just to one resistor, the resistor in this case we choose 2k but the essential is to show that the resistors usually don't have the same value. applying to the 2k resistor we have:
so.
Answer:
The other angle is 30 degrees.
Explanation:
The range of projectile is given by :
Here,
u is the speed of launch of projectile
Here,
We need to find the other launch angle when the projectile have the same range, such that,
So, the other angle is 30 degrees. Hence, this is the required solution.
Answer:
The resistance will be 2×R
Explanation:
We note that the resistivity of a cylindrical wire is given by the following relation;
Where:
ρ = Resistivity of the wire
R = The wire resistance
A = Cross sectional area of the wire = π·D²/4
L = Length of the wire
Rearranging, we have;
If the length and the diameter are both cut in half, we have;
L₂ = L/2
A₂ =π·D₂²/4 =
Therefore, the new resistance, R₂ can be expressed as follows;
Hence, the new resistance R₂ = 2×R, that is the resistance will be doubled.