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Katyanochek1 [597]
2 years ago
15

A brick and a feather fall to the earth at their respective terminal velocities. which object experiences the greater force of a

ir resistance?
Physics
2 answers:
horsena [70]2 years ago
6 0
The brick, even though the brick would end up traveling faster, it most likely has a larger surface area therefore it would have more air resistance.
satela [25.4K]2 years ago
5 0

Answer:

since brick is heavy than feather so at that time air resistance on brick will be more than the air resistance on feather

Explanation:

When an object will reach at its terminal velocity then the acceleration of that object will become ZERO

So at that moment of time we can say that net force on the object must be zero or the force of gravity due to its weight is counter balanced by air friction on the object

So when brick will reach to its terminal speed then we have

F_air = m_{brick} g

when feather will reach to its terminal speed

F_{air} = m_{feather} g

so here we can say that since brick is heavy than feather so at that time air resistance on brick will be more than the air resistance on feather

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A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
krok68 [10]

Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

8 0
2 years ago
Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to
vesna_86 [32]

Answer:

The speed and direction of the apple is 1.448 m/s and 66.65°.

Explanation:

Given that,

Mass of apple = 0.110 kg

Speed = 1.13 m/s

Mass of orange = 0.150 kg

Speed = 1.25 m/s

Suppose we find the final speed and direction of the apple in this case

Using conservation of momentum:

Before:

In x direction,

P_{b}=m_{p}v_{p}-m_{o}v_{o}

P_{b}=0.110\times1.13-0.150\times1.25

P_{b}=−0.0632\ kg-m/s

In y direction = 0

After:

v_{ay} is velocity of the apple in the y direction

v_{ax} is the velocity of the apple in the x direction

Momentum again:

In x direction,

0.110\times v_{ax}+0=−0.0632

v_{x}=\dfrac{−0.0632}{0.110}

v_{x}=−0.574\ m/s

In y-direction,

0.110\times v_{ay}-0.150\times0.977=0

v_{ay}=\dfrac{0.150\times0.977}{0.110}

v_{ay}=1.33\ m/s

We need to calculate the speed of apple

v_{a}=\sqrt{(v_{x})^2+(v_{y})^2}

Put the value into the formula

v_{a}=\sqrt{(−0.574)^2+(1.33)^2}

v_{a}=1.448\ m/s

We need to calculate the direction of the apple

Using formula of angle

\tan\theta=\dfrac{v_{ay}}{v_{ax}}

Put the value into the formula

\theta=\tan^{-1}(\dfrac{1.33}{0.574})

\theta=66.65^{\circ}

Hence, The speed and direction of the apple is 1.448 m/s and 66.65°.

3 0
2 years ago
A bicyclist is riding at a tangential speed of 13.2 m/s around a circular track. The magnitude of the centripetal force is 377 N
MA_775_DIABLO [31]

Answer:

40m approximately

Explanation:

Given

Force =377N

Mass =86.5kg

Velocity =13.2m/s

Required

Radius of the track

The expression for the centripetal force acting on the cyclist is

F=mv²/r

Make r subject of the formula

r= mv²/F

Substitute

r=86.5*13.2²/377

r= 15,071.76/377

r=39.97

r=40m approximately

4 0
2 years ago
An object’s velocity is measured to be vx(t) = α - βt2, where α = 4.00 m/s and β = 2.00 m/s3. At t = 0 the object is at x = 0. (
Leona [35]

Answer:

Explanation:

Given

v_x(t)=\alpha -\beta t^2

\alpha =4\ m/s

\beta =2\ m/s^3

v_x(t)=4-2t^2

v=\frac{\mathrm{d} x}{\mathrm{d} t}

\int dx=\int \left ( 4-2t^2\right )dt

x=4t-\frac{2}{3}t^3

acceleration of object

a=\frac{\mathrm{d} v}{\mathrm{d} t}

a=-4t

(b)For maximum positive displacement velocity must be zero at that instant

i.e.v=0

4-2t^2=0

t=\pm \sqrt{2}

substitute the value of t

x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}

x=3.77\ m

7 0
2 years ago
Determine the scalar components Ra and Rb of the force R along the nonrectangular axes a and b. Also determine the orthogonal pr
Liula [17]

Answer: Hello your question is incomplete attached below is the complete question

Ra = 1132 N

Rb = 522.6 N

Pa = 679.7 N

Explanation:

To determine the scalar components Ra

\frac{Ra}{Sin 120^o} = \frac{750}{sin 35^o}  

therefore : Ra = \frac{sin120^o * 750}{sin 35^o} = 1132 N

To determine the scalar component Rb

\frac{Rb}{sin 25^o} = \frac{750}{sin 35^o}

therefore : Rb = \frac{sin 25^o * 750}{sin 35^o}  = 522.6 N

To determine the orthogonal projection Pa of R onto

Pa = 750 cos25^o = 679.7 N

6 0
2 years ago
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