Answer:
The correct answer is a rarefaction.
Explanation:
Sound waves are longitudinal waves that propagate in a medium, such as air. As the vibration continues, a series of successive condensations and rarefactions form and propagate from it. The pattern created in the air is something like a sinusoidal curve to represent a sound wave.
There are peaks in the sine wave at the points where the sound wave has condensations and valleys where it has rarefactions.
Have a nice day!
<span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400
This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.
Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.
Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600
This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.
Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)
The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.
x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>
Answer:
Explanation:
Height reached by the object after push off is given as
now we have
now we know that this push last for total distance of 0.18 m
so during the push we will have
now in terms of g = 9.81 m/s/s we have
Answer:
55mg/kg * 0.02kg which gives 1.1 mg pesticides
Explanation:
(Options are missing)
If the average mass or weight of a roach is 0.02kg
And 55mg is needed per 1 kg roaches
The amount or size of pesticide required for 0.02kg roach is 55mg/kg * 0.02kg
Size = 55mg/kg * 0.02 kg
Size = 1.1mgkg/kg
Size = 1.1 mg
So, the size of pesticide required is 1.1mg
Answer:
V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)
Explanation:
Attached is the full solution
