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LenKa [72]
2 years ago
12

Takumi works in his yard for 45 minutes each Saturday. He works in the morning, and he wears sunscreen and a hat each time he wo

rks in the yard.
What does Takumi hope to reduce through his actions?

the likelihood of stochastic effects, such as DNA mutations
the severity of stochastic effects, such as cancer
the severity of non-stochastic effects, such as cancer
the likelihood of non-stochastic effects, such as radiation sickness
Physics
2 answers:
MrRa [10]2 years ago
7 0

Explanation :

Takumi wears sunscreen and a hat each time he works in the yard. This is to protect himself with the strong radiation coming from the sun. UV rays that are coming from the sun are the main cause of skin cancer.

Stochastic effects are the effects that are caused by chance. Cancer is one of the main stochastic effects.

So, the correct option is (b) "the severity of stochastic effects, such as cancer".

givi [52]2 years ago
5 0

Answer:its A

Explanation:

i took the test

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A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?
OLga [1]

v=v2-v1=15-10=5 cm/s

p=mv=0.15•5=0.75 kg•cm/s

7 0
2 years ago
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You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
kati45 [8]

Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

   The  length of the lane is  l =  36.0 \  m

    The speed of the truck is  v  =  22.6\  m/s

     

Generally from the work-energy theorem we have that  

    \Delta KE  =   N  *  \mu_k *  l

Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

        \Delta KE =  \frac{1}{2} *  m *  v^2

=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

        255.38m =    m *  9.8  *  \mu_k *   36.0

=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
2 years ago
At 213.1 K a substance has a vapor pressure of 45.77 mmHg. At 243.7 K it has a vapor pressure of 193.1 mm Hg. Calculate its heat
vlabodo [156]

Answer:

20.3125 kJ/mol

Explanation:

P_{i} = initial vapor pressure = 45.77 mm Hg

P_{f} = final vapor pressure = 193.1 mm Hg

T_{i} = initial temperature = 213.1 K

T_{f} = final temperature = 243.7 K

H = Heat of vaporization

Using the equation

ln\left ( \frac{P_{f}}{P_{i}} \right ) = \left ( \frac{-H}{R} \right )\left ( \frac{1}{T_{f}} - \frac{1}{T_{i}}\right)

ln\left ( \frac{193.1}{45.77} \right ) = \left ( \frac{-H}{8.314} \right )\left ( \frac{1}{243.7} - \frac{1}{213.1}\right)

H = 20312.5 J/mol

H = 20.3125 kJ/mol

8 0
2 years ago
If a scale on Earth reads 650 N, what is your mass?
OlgaM077 [116]
If the scale reads 650N, then the mass of whoever it is standing on the scale is

         (weight) / (gravity)  =  (650N) / (9.8 m/s²)  =  66.3 kilograms  .

It's not MY mass, even if I'm the one standing on the scale. 
If I stand on a scale and it reads 650 N, the scale is broken.
4 0
2 years ago
A 0.28-kg stone you throw rises 34.3 m in the air. The magnitude of the impulse the stone received from your hand while being th
goldfiish [28.3K]

Answer:

7.3 kg m/s

Explanation:

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U=mgh=(0.28 kg)(9.8 m/s^2)(34.3 m)=94.1 J

For the law of conservation of energy, this is equal to the initial kinetic energy of the stone at ground level (where the potential energy is zero), just after the stone leaves your hand:

K=\frac{1}{2}mv^2=94.1 J

From this equation we can find the velocity of the stone as it leaves your hand:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(94.1 J)}{0.28 kg}}=25.9 m/s

The initial velocity of the stone (before leaving your hand) is zero:

u=0

The impulse received by the stone is equal to its change in momentum, so:

I=\Delta p=m\Delta v=m(v-u)=(0.28 kg)(25.9 m/s-0)=7.3 kg m/s

5 0
2 years ago
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