acceleration of rocket is given here as
now we know that
now integrating both sides
here since its given that rocket will accelerate for t = 10 s
so here we have
so after t = 10 s the speed of rocket will be 130 m/s upwards
Find the time t1 it takes to accelerate the flywheel to ω1 if the angular acceleration is α. express your answer in terms of ω1
2 answers:
the time t1 it takes to accelerate:
The speed of the rotating object is called angular velocity. This value is part of circular motion.
The angular velocity is denoted by w including the vector quantity. The unit used is usually rpm (rotation per minute) or radians / sec
Average angular velocity is the ratio of angular displacement to the time interval
Circular motion with constant acceleration (angular acceleration denoted by α) can be formulated:
ωo = initial angular velocity
ω = angular velocity after t
the flywheel accelerate to ω1, so:
wo = 0 because The flywheel is assumed to be at rest at time t = 0
so the equation becomes:
ω1 = ωo + αt
ω1 = 0 + αt
ω1 = αt
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Answer:
Isothermal : P2 = ( P1V1 / V2 ) , work-done
Adiabatic : : P2 = , work-done =
W =
Explanation:
initial temperature : T
Pressure : P
initial volume : V1
Final volume : V2
A) If expansion was isothermal calculate final pressure and work-done
we use the gas laws
= PIVI = P2V2
Hence : P2 = ( P1V1 / V2 )
work-done :
B) If the expansion was Adiabatic show the Final pressure and work-done
final pressure
where y = 5/3
hence : P2 =
Work-done
W =
Where