Answer:
W = 506.75 N
Explanation:
tension = 2300 N
Rider is towed at a constant speed means there no net force acting on the rider.
hence taking all the horizontal force and vertical force in consideration.
net horizontal force:
F cos 30° - T cos 19° = 0
F cos 30° = 2300 × cos 19°
F = 2511.12 N
net vertical force:
F sin 30° - T sin 19°- W = 0
W = F sin 30° - T sin 19°
W = 2511.12 sin 30° - 2300 sin 19°
W = 506.75 N
Answer:
2.45 m
Explanation:
First of all, we have to calculate the time of flight of the book, by using the equation for the vertical motion:
where
h = 1.19 m is the vertical distance covered by the book
g = 9.8 m/s^2 is the acceleration of gravity
t is the time of flight
Solving for t,
Now we can find the horizontal distance covered by the book, which is given by
where
is the horizontal velocity
t = 0.49 s is the time of flight
Substituting,
So the book lands 2.45 m away.
Answer:
B. The truck and mosquito exert the same size force on each other.
Explanation:
Newton's third law (law of action-reaction) states that
"When an object A exerts a force (action) on an object B, then object B exerts an equal and opposite force (reaction) on object A"
In this case, we can call
object A = the truck
object B = the mosquito
Thereforce according to Newton's third law, the force exerted by the truck on the mosquito is equal in magnitude to the force exerted by the mosquito on the truck (and in opposite direction).
The reason for which the mosquito will experience much more damage is the fact that the mosquito's mass is much smaller than the truck's mass, and since the acceleration is inversely proportional to the mass:
the mosquito will experience a much larger deceleration than the truck, therefore much more damage.
Answer:
0.04328 H
0.00288 seconds
0.01326 seconds
Explanation:
V = Voltage = 6.3 V
R = Resistance = 15 Ω
L = Inductance
I = Decayed current = 0.21 A
t = Time to decay = 2 ms
Maximum Current is given by
Current in the circuit is given by
The inductance is 0.04328 H
Time constant is given by
Time constant is 0.00288 seconds
Time required is given by
The time to reach 1% of its original value is 0.01326 seconds