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2 years ago

8

In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r

ider is towed at a constant speed by a rope that is at an angle of 19 ∘ from horizontal. The tension in the rope is 2300 N. The force of the sail on the rider is 30∘ from horizontal.What is the weight of the rider?

1 answer:

scoray [572]2 years ago

8 0

Answer:

W = 506.75 N

Explanation:

tension = 2300 N

Rider is towed at a constant speed means there no net force acting on the rider.

hence taking all the horizontal force and vertical force in consideration.

net horizontal force:

F cos 30° - T cos 19° = 0

F cos 30° = 2300 × cos 19°

F = 2511.12 N

net vertical force:

F sin 30° - T sin 19°- W = 0

W = F sin 30° - T sin 19°

W = 2511.12 sin 30° - 2300 sin 19°

W = 506.75 N

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Calculate the mass of the air contained in a room that measures 2.50 m x 5.50 m x 3.00 m if the density of air is 1.29 g/dm3.53.

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First of all, we need to find the volume of the room, which is given by

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Now we can find the mass of the air by using

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