In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
ider is towed at a constant speed by a rope that is at an angle of 19 ∘ from horizontal. The tension in the rope is 2300 N. The force of the sail on the rider is 30∘ from horizontal.What is the weight of the rider?
1 answer:
Answer:
W = 506.75 N
Explanation:
tension = 2300 N
Rider is towed at a constant speed means there no net force acting on the rider.
hence taking all the horizontal force and vertical force in consideration.
net horizontal force:
F cos 30° - T cos 19° = 0
F cos 30° = 2300 × cos 19°
F = 2511.12 N
net vertical force:
F sin 30° - T sin 19°- W = 0
W = F sin 30° - T sin 19°
W = 2511.12 sin 30° - 2300 sin 19°
W = 506.75 N
You might be interested in
Answer:
Explanation:
Given:
Initial velocity of the vehicle,
distance between the car and the tree,
time taken to respond to the situation,
acceleration of the car after braking,
Using equation of motion:
..............(1)
where:
final velocity of the car when it hits the tree
initial velocity of the car when the tree falls
acceleration after the brakes are applied
distance between the tree and the car after the brakes are applied.
Now for this situation the eq. (1) becomes:
(negative sign is for the deceleration after the brake is applied to the car.)
Answer:
Mass of bike = 38 kg.
Explanation:
Kinetic energy is given by the expression, , where m is the mass and v is the velocity.
Here speed of child riding bike = 6 m/s
Mass of child = 30 kg
Total kinetic energy = 1224 J
Let the mass of bike be, m kg
So, total mass of child and bike = (m + 30) kg
Substituting,
So, mass of bike = 38 kg.
Answer:
3. none of these
Explanation:
The rotational kinetic energy of an object is given by:
where
I is the moment of inertia
is the angular speed
In this problem, we have two objects rotating, so the total rotational kinetic energy will be the sum of the rotational energies of each object.
For disk 1:
For disk 2:
so the total energy is
So, none of the options is correct.