A bullet is fired horizontally, and at the same instant a second bullet is dropped from the same height. Ignore air resistance.
1 answer:
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Ans: Beat Frequency = 1.97Hz
Explanation:
The fundamental frequency on a vibrating string is
<span> -- (A)</span>
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>
<span> = 197.97Hz </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>
Explanation:
The fundamental frequency on a vibrating string is
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>
Answer:
Mass, m of gas is 0.2504 grams.
Explanation:
First, we need to solve for the volume of the cylindrical tube.
Volume of cylinder is given by the formula;
Where, V represents volume.
π represents pie
r represents radius.
h represents height or length.
Given the following data;
Radius, r = 1.5cm
Length, h = 14.4cm
Density, d = 0.00123g/cm³
Substituting into the equation;
Therefore, the volume of the cylindrical tube is 203. 6016cm³
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the formula;
Substituting into the equation, we have;
Mass = 0.2504g.
Answer:
(c) +6.67
Explanation:
f1 = 10 cm
f2 = 20 cm
u = Object distance = 15 cm
Distance between lenses = 20 cm
For first lens image distance
Distance from second lens is 10 cm to the right
The final image will appear as +6.67 cm