A bullet is fired horizontally, and at the same instant a second bullet is dropped from the same height. Ignore air resistance.
1 answer:
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Explanation:
Given that,
Angular velocity = 0.240 rev/s
Angular acceleration = 0.917 rev/s²
Diameter = 0.720 m
(a). We need to calculate the angular velocity after time 0.203 s
Using equation of angular motion
Put the value in the equation
The angular velocity is 0.426 rev/s.
(b). We need to calculate the tangential speed of the blade
Using formula of tangential speed
Put the value into the formula
The tangential speed of the blade is 0.963 m/s.
(c). We need to calculate the magnitude at of the tangential acceleration
Using formula of tangential acceleration
Put the value into the formula
The tangential acceleration is 2.074 m/s².
Hence, This is required solution.