three point charges are positioned on the x-axis 64 uc at x=ocm , 80uc at x=25cm, and -160 uc at x=50 cm. what is the magnitude
1 answer:
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Answer:
h = v₀² / 2g , h = k/4g x²
Explanation:
In this exercise we can use the law of conservation of energy at two points, the lowest, before the shot and the highest point that the mouse reaches
Starting point. Lower compressed spring
Em₀ = K = ½ m v²
Final point. Highest on the path
= U = mg h
As or no friction the energy is conserved
Em₀ = Em_{f}
½ m v₀²² = m g h
h = v₀² / 2g
We can also use as initial energy the energy stored in the spring that will later be transferred to the mouse
½ k x² = 2 g h
h = k/4g x²
Answer:
Fe= 2579.68 P
α= 24.8°
Explanation:
Look at the attached graphic
we take the forces acting on the x-y plane and applied at the origin of coordinates
FX = 1260 P , horizontal (-x)
FY = 1530 P , forming 45° with positive x axis
x-y components FY
FYx= - 1530*cos(45)° = - 1081.87 P
FYy= - 1530*sin(45)° = - 1081.87 P
Calculation of the components of net force (Fn)
Fnx= FX + FYx
Fnx= -1260 P -1081.87 P
Fnx= -2341.87 P
Fny=FYy
Fny= -1081.87 P
Calculation of the components of equilibrant force (Fe)
the x-y components of the equilibrant force are equal in magnitude but in the opposite direction to the net force components:
Fnx= -2341.87 P, then, Fex= +2341.87 P
Fny= -1081.87 P P, then, Fex= +1081.87 P
Magnitude of the equilibrant (Fe)
Fe= 2579.68 P
Calculation of the direction of equilibrant force (α)
α= 24.8°
Look at the attached graphic
Answer:
binding energy is 99771 J/mol
Exlanation:
given data
threshold frequency = 2.50 × Hz
solution
we get here binding energy using threshold frequency of the metal that is express as
..................1
here E is the energy of electron per atom and h is plank constant i.e.
and x is binding energy
and here N is the Avogadro constant =
so E will
E =
so put value in equation 1 we get
= 2.50 ×
×
solve it we get
x = 99770.99
so binding energy is 99771 J/mol