Answer:
C.Step-Down
Explanation:
Given that
Number of turn in the primary N₁= 1000
Secondary current I₂= 600 mA
Secondary voltage V₂= 8 V
Primary voltage V₁= 400 V
From the above information we can say that output voltage is low compare to input voltage.
V₂ < V₁
We know that if
1 . V₂ < V₁ - Then transformer will be step down .
2. V₂ > V₁ - Then transfer will be step up .
Here
V₂ < V₁ ( 8 V < 400 V)
So the transformer is step down transformer.
C.Step-Down
Point X lies on a horizontal line. We can intuitively say that the slope of the graph at point X is 0, therefore the acceleration at point X is 0m/s²
Point Y lies on a downward slanting line. To calculate the slope of that line, let's apply this equation:
m = (y₂-y₁)/(x₂-x₁)
m = slope, (x₁, y₁) and (x₂, y₂) correspond to the coordinates of the line's endpoints.
Given values:
(x₁, y₁) = (7, 5)
(x₂, y₂) = (12, 0)
Plug in and solve for m:
m = (0 - 5)/(12 - 7)
m = -1
The acceleration at point Y is -1m/s²
Choice A
Answer:
26.56°
Explanation:
μ= 0.5
F = ?
N =?
Fs = μN
Fs = force acting due to friction (on an inclined plane)
N = normal force.
μ= coefficient of friction
μ= tanΘ
μ= tan 0.5
Θ = tan⁻¹ 0.5
Θ = 26.56°
The angle in which is required for the box to start moving across the inclined plane is 26.56°
Answer:
(a) 0.84 s
(b) 8.22 m/s
(c) 15.33 m/s
Explanation:
u = 0 , h = 3.45 m, g = 9.8 m/s^2
Let time taken to reach the water is t and the velocity at the time of hitting of water surface is v.
(a) Use first equation of motion
s = u t + 1/2 a t^2
3.45 = 0 + 0.5 x 9.8 x t^2
t = 0.84 second
(b) Use first equation of motion
v = u + a t
v = 0 + 9.8 x 0.84 = 8.22 m/s
(c) If h = 12 m
use third equation of motion
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 12
v = 15.33 m / s
Answer:
80 J
Explanation:
Ep = mgh
Ep = (4 kg) (10 m/s²) (2 m)
Ep = 80 J
