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sleet_krkn [62]
1 year ago
6

A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the spee

d of the train relative to the girl?
Physics
2 answers:
sineoko [7]1 year ago
6 0

Answer:

velocity of the train with respect to girl is 85 m/s

Explanation:

As we know that girl is moving towards the train in front of it with speed

v_1 = 10 m/s

also we know that the speed of the train towards the girl is

v_2 = 75 m/s

Now we know that relative velocity of the train with respect to girl is given as

\vec v_{tg} = \vec v_t - \vec v_g

here let say the velocity of train is positive while girl is running opposite to train so its velocity is negative

\vec v_{tg} = 75 m/s - (-10 m/s)

\vec v_{tg} = 85 m/s

dimulka [17.4K]1 year ago
5 0
We can take as positive direction the direction of the train, and as negative direction the direction of the girl. The speed of the train relative to the girl will be given by the difference between the two velocities:
v' = v_t - v_g
which means
v'=75 m/s - (-10 m/s)=85 m/s
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Answer:

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GuDViN [60]

Answer:

The total charge on the rod is 47.8 nC.

Explanation:

Given that,

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The electric field intensity due to a uniformly charged rod of length L at a distance x on its perpendicular bisector

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E=\dfrac{kQ}{x\sqrt{(\dfrac{L}{2})^2+x^2}}

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Using formula of force

F=qE

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Q=\dfrac{Fx\sqrt{(\dfrac{L}{2})^2+x^2}}{kq}

Put the value into the formula

Q=\dfrac{840\times10^{-6}\times4.0\times10^{-2}\sqrt{(\dfrac{10.0\times10^{-2}}{2})^2+(4.0\times10^{-2})^2}}{9\times10^{9}\times5.0\times10^{-9}}

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2 years ago
After an incandescent lamp is turned on, the temperature of its filament rapidly increases from room temperature to its operatin
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6 0
1 year ago
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photoshop1234 [79]
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</span><span> where 
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jeka94

answer:

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hope it's help!

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