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Norma-Jean [14]
2 years ago
14

A 500 kg motorcycle accelerates at a rate of 2 m/s .how much force was applied to the motorcycle?

Physics
2 answers:
Aleksandr [31]2 years ago
8 0

Answer:

by using formula F=ma which is m stand for mass a stand for acceleration. so 500kg × 2 ms^-2

Kamila [148]2 years ago
8 0
Hope this helped, click

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An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance
bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 \frac{m}{sec}

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion V^{2} = u^{2} - 2 a s

Put all the values in above formula we get,

⇒ 0 = 0.8^{2} - 2 × a ×0.2667

⇒ a = 1.2 \frac{m}{sec^{2} }

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0
2 years ago
A quarterback throws a football at 40km/hr to a receiver 50yd away. How much time does it take the ball to reach the receiver
Akimi4 [234]

Given:

Distance = 50 yard = 45.72 meter

Speed = 40 km/hr = 11.11 m/s

To find:

Time required by ball to reach the receiver = ?

Formula used:

speed = \frac{distance}{time}

Solution:

The speed of the ball is given by,

speed = \frac{distance}{time}

Thus,

Time = \frac{distance}{speed}

Distance = 50 yard = 45.72 meter

Speed = 40 km/hr = 11.11 m/s

Time = 4.12 second

Hence, ball reaches the receiver in 4.12 second.

3 0
2 years ago
A father demonstrates projectile motion to his children by placing a pea on his fork's handle and rapidly depressing the curved
MariettaO [177]

Answer:

4.17 m/s

Explanation:

To solve this problem, let's start by analyzing the vertical motion of the pea.

The initial vertical velocity of the pea is

u_y = u sin \theta = (7.39)(sin 69.0^{\circ})=6.90 m/s

Now we can solve the problem by applying the suvat equation:

v_y^2-u_y^2=2as

where

v_y is the vertical velocity when the pea hits the ceiling

a=g=-9.8 m/s^2 is the acceleration of gravity

s = 1.90 is the distance from the ceiling

Solving for v_y,

v_y = \sqrt{u_y^2+2as}=\sqrt{(6.90)^2+2(-9.8)(1.90)}=3.22 m/s

Instead, the horizontal velocity remains constant during the whole motion, and it is given by

v_x = u cos \theta = (7.39)(cos 69.0^{\circ})=2.65 m/s

Therefore, the speed of the pea when it hits the ceiling is

v=\sqrt{v_x^2+v_y^2}=\sqrt{2.65^2+3.22^2}=4.17 m/s

5 0
2 years ago
The formation of magma within Earth is NOT caused by which of the following processes? A. decompression (drop in pressure) B. ad
Lunna [17]

Answer:

D. loss of volatiles to the atmosphere

Explanation:

The name magma designates matter in a semi-fluid state - resulting from the fusion of silicates containing dispersed solid gases and minerals and other compounds that make up the rocks, at temperatures between 700 and 1200 ° C - that forms the region beneath the crust. land. When it is inside the earth it is specifically named magma and lava when it is ejected to the surface

There are three systems by which magma can be produced on earth:

<u> Temperature</u> rise by concentration of r<u>adioactive elements or by friction of lithospheric plates</u>.

<u> Pressure decrease,</u> since the melting point decreases.

Adding <u>water</u> A rock begins to melt earlier if it contains water because the –OH groups effectively break the Si-O bonds.

A rock is formed by a set of minerals, each of which has a characteristic melting point so a rock does not have a single melting point but a temperature range in which the rock melts into parts, leaving others solid parts. Between the point at which a solid rock begins to melt and the melting end (liquid point) the rock is partially molten.

The rise of magmas depends on their physical-chemical conditions (viscosity, density, volatile element content), on the tectonic peculiarities of the region where they are found and on the rocks to be traversed. Acid magmas are light and viscous, rise easily and cause large deposits. The basic magmas, of greater density, are less viscous and ascend with greater difficulty than the previous ones.

8 0
2 years ago
If the force of gravity between a book of mass 0.50 kg and a calculator of 0.100 kg is 1.5 × 10-10 N, how far apart are they?  (
valkas [14]
The gravitational force between two masses m₁ and m₂ is
F=G \frac{m_{1} m_{2}}{d^{2}}
where
G = 6.67408 x 10⁻¹¹ m³/(kg-s²), the gravitational constant
d =  distance between the masses.

Given:
F = 1.5 x 10⁻¹⁰ N
m₁ = 0.50 kg
m₂ = 0.1 kg

Therefore
1.5 x 10⁻¹⁰ N = (6.67408 x 10⁻¹¹ m³/(kg-s²))*[(0.5*0.1)/(d m)²]
d² = [(6.67408x10⁻¹¹)*(0.5*0.1)]/1.5x10⁻¹⁰
     = 0.0222
d = 0.1492 m = 149.2 mm

Answer: 149.2 mm
8 0
2 years ago
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