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valina [46]
1 year ago
13

While a car is stopped at a traffic light in a storm, raindrops strike the roof of the car. The area of the roof is 5.0 m2. Each

raindrop has a mass of 3.7 ✕ 10−4 kg and speed of 2.5 m/s before impact and is at rest after the impact. If, on average at a given time, 150 raindrops strike each square meter, what is the impulse of the rain striking the car?
Physics
1 answer:
julsineya [31]1 year ago
5 0

Answer:

J = 0.693 N.s

Explanation:

The impulse of one single drop is given by:

J1 = m*(Vf - Vo)   where Vf = 0

J1 = -9.25*10^{-4}N.s

The magnitude of the total impulse will be:

Jt = J1 * 150 * 5

Jt = 0.693 N.s

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Answer:

energy carried by the current is given by the pointyng vector

Explanation:

The current is defined by

       i = dQ / dt

this is the number of charges per unit area over time.

The movement of the charge carriers (electrons) is governed by the applied potential difference, when the filament has a movement the drag speed of these moving electrons should change slightly.

But the energy carried by the current is given by the pointyng vector of the electromagnetic wave

            S = 1 / μ₀ EX B

It moves at the speed of light and its speed depends on the properties of the doctor and is not disturbed by small changes in speed, therefore the current in the circuit does not change due to this movement

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2 years ago
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2 years ago
In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of a
fgiga [73]

(a) The diffraction decreases

The formula for the diffraction pattern from a single slit is given by:

sin \theta = \frac{n \lambda}{a}

where

\theta is the angle corresponding to nth-minimum in the diffraction pattern, measured from the centre of the pattern

n is the order of the minimum

\lambda is the wavelength

a is the width of the opening

As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because \theta increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.

(b) 10.8^{\circ}

The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:

sin \theta = \frac{(1) \lambda}{a}

in this case we have

\lambda=54 cm = 0.54 m is the wavelength

a=5.7 m is the width of the opening

Solving the equation, we find

\theta = sin^{-1} (\frac{\lambda}{a})=sin^{-1} (\frac{0.54 m}{5.7 m})=5.4^{\circ}

So the angular spread of the central diffraction maximum is twice this angle:

\theta = 2 \cdot 5.4^{\circ}=10.8^{\circ}

(c) 0.26^{\circ}

Here we can apply the same formula used before, but this time the wavelength of the signal is

\lambda=13 mm=0.013 m

so the angle corresponding to the first minimum is

\theta = sin^{-1} (\frac{\lambda}{a})=sin^{-1} (\frac{0.013 m}{5.7 m})=0.13^{\circ}

So the angular spread of the central diffraction maximum is twice this angle:

\theta = 2 \cdot 0.13^{\circ}=0.26^{\circ}

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1 year ago
A runner runs around the track consisting of two parallel lines 96 m long connected at the ends by two semi circles with a radiu
Zielflug [23.3K]
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2 years ago
When a gas is rapidly compressed (say, by pushing down a piston) its temperature increases. When a gas expands against a piston,
shusha [124]

Answer:

Explained in explanation

Explanation:

The first law of thermodynamics states that the change in internal energy of a system(ΔU) is equal to the sum of the net heat transfer into the system(Q) and the net work done on the system(W). In equation, this law is;

ΔU = Q + W

Now, when there's gas inside a container with a movable piston that's tightly fitting, we will assume that the piston can move up and down thereby compressing the gas or allowing the gas to expand against it.

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Therefore, if the temperature(T) of the gas increases, then the speed and internal energy(U) of the gas molecules will also increase. In the same way, if the temperature of the gas decreases, the speed and internal energy of the gas molecules would also decrease.

Now, back to the question, when the piston is pushed down, it does work on the gas and the gas does negative work on the piston. Thus, the gas will be get compressed to a smaller space, and thereby making the gas molecules to hit the piston at a faster rate. Thus, there is a decrease in speed and as we saw earlier that when there is a decrease in speed, it means temperature has decreased.

Whereas, when the piston is moved up, the gas does positive work on the piston and the speed of the gas molecules will increase. Like I said earlier that increase in speed means increase in temperature.

4 0
1 year ago
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