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ser-zykov [4K]
1 year ago
11

A toy car has a battery-powered fan attached to it such that the fan creates a constant force that is exerted on the car so that

it is propelled in the opposite direction in which the fan blows air. The car has a carriage that allows a student to attach objects of different masses, as shown above. The fan has only one speed setting. All frictional forces are considered to be negligible. Which of the following procedures could be used to determine how the mass of the fan-car-object system affects the acceleration of the system?
Physics
2 answers:
Andreas93 [3]1 year ago
7 0

Answer:

Measure the mass of the system using a balance, activate the fan, measure the distance traveled by the system at a known time by using a stopwatch, and repeat the experiment for several trials with different objects added to the carriage.

Explanation:

swat321 year ago
4 0

Procedures <em><u>point C</u></em> could be used to determine how the mass of the fan-car-object system affects the acceleration of the system

<h3>Further explanation </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

<h3>∑F = m. a </h3>

\large{\boxed{\bold{a=\frac{\sum F}{m}}}

F = force, N

m = mass = kg

a = acceleration due to gravity, m / s²

we complete the available answer choices

A).Measure the mass of the system using a balance, activate the fan, measure the distance traveled by the system at a known time by using a stopwatch, and repeat the experiment for several trials with different objects added to the carriage.

B) Measure the mass of the system using a balance, activate the fan, use a meterstick and stopwatch to measure the initial and final speeds of the system, and repeat the experiment for several trials with different objects added to the carriage.

C)Measure the mass of the system using a balance, connect a spring scale to the back of the car, measure the amount of force required to hold the system at rest, and repeat the experiment for several trials with different objects added to the carriage.

D)Measure the mass of the system using a balance, activate the fan, use a stopwatch to record the time it takes for the system to travel before the battery of the fan no longer works, and repeat the experiment for several trials with different objects added to the carriage.

From the choices above, we choose point C because to find out the effect of mass on acceleration, we need the force value (F) from the spring scale and the mass of objects of different masses using a balance

If we look at the formula, we can analyze and estimate that the greater the mass given, the smaller the system acceleration

<h3>Learn more</h3>

law of motion  

brainly.com/question/75210  

displacement of A skateboarder

brainly.com/question/1581159

The distance of the elevator  

brainly.com/question/8729508  

Keywords : system acceleration, A toy car, fan

#LearnWithBrainly

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An ideal gas is contained in a vessel at 300 K. The temperature of the gas is then increased to 900 K. (i) By what factor does t
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The question is missing some parts. Here is the complete question.

An ideal gas is contained in a vessel at 300K. The temperature of the gas is then increased to 900K.

(i) By what factor does the average kinetic energy of the molecules change, (a) a factor of 9, (b) a factor of 3, (c) a factor of \sqrt{3}, (d) a factor of 1, or (e) a factor of \frac{1}{3}?

Using the same choices in part (i), by what factor does each of the following change: (ii) the rms molecular speed of the molecules, (iii) the average momentum change that one molecule undergoes in a colision with one particular wall, (iv) the rate of collisions of molecules with walls, and (v) the pressure of the gas.

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              (ii) (c) a factor of \sqrt{3};

              (iii) (c) a factor of \sqrt{3};

             (iv) (c) a factor of \sqrt{3};

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n is mols

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T is temperature in Kelvin

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(ii) Rms is root mean square velocity and is defined as

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For 300K:

V_{rms1}=\sqrt{\frac{3k_{B}300}{m} }

V_{rms1}=30\sqrt{\frac{k_{B}}{m} }

For 900K:

V_{rms2}=\sqrt{\frac{3k_{B}900}{m} }

V_{rms2}=30\sqrt{3}\sqrt{\frac{k_{B}}{m} }

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