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ser-zykov [4K]
2 years ago
11

A toy car has a battery-powered fan attached to it such that the fan creates a constant force that is exerted on the car so that

it is propelled in the opposite direction in which the fan blows air. The car has a carriage that allows a student to attach objects of different masses, as shown above. The fan has only one speed setting. All frictional forces are considered to be negligible. Which of the following procedures could be used to determine how the mass of the fan-car-object system affects the acceleration of the system?
Physics
2 answers:
Andreas93 [3]2 years ago
7 0

Answer:

Measure the mass of the system using a balance, activate the fan, measure the distance traveled by the system at a known time by using a stopwatch, and repeat the experiment for several trials with different objects added to the carriage.

Explanation:

swat322 years ago
4 0

Procedures <em><u>point C</u></em> could be used to determine how the mass of the fan-car-object system affects the acceleration of the system

<h3>Further explanation </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

<h3>∑F = m. a </h3>

\large{\boxed{\bold{a=\frac{\sum F}{m}}}

F = force, N

m = mass = kg

a = acceleration due to gravity, m / s²

we complete the available answer choices

A).Measure the mass of the system using a balance, activate the fan, measure the distance traveled by the system at a known time by using a stopwatch, and repeat the experiment for several trials with different objects added to the carriage.

B) Measure the mass of the system using a balance, activate the fan, use a meterstick and stopwatch to measure the initial and final speeds of the system, and repeat the experiment for several trials with different objects added to the carriage.

C)Measure the mass of the system using a balance, connect a spring scale to the back of the car, measure the amount of force required to hold the system at rest, and repeat the experiment for several trials with different objects added to the carriage.

D)Measure the mass of the system using a balance, activate the fan, use a stopwatch to record the time it takes for the system to travel before the battery of the fan no longer works, and repeat the experiment for several trials with different objects added to the carriage.

From the choices above, we choose point C because to find out the effect of mass on acceleration, we need the force value (F) from the spring scale and the mass of objects of different masses using a balance

If we look at the formula, we can analyze and estimate that the greater the mass given, the smaller the system acceleration

<h3>Learn more</h3>

law of motion  

brainly.com/question/75210  

displacement of A skateboarder

brainly.com/question/1581159

The distance of the elevator  

brainly.com/question/8729508  

Keywords : system acceleration, A toy car, fan

#LearnWithBrainly

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mL    - fl oz

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200.01 6.7631

200.02 6.7635

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200.04 6.7642

200.05 6.7645

200.06 6.7648

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200.08 6.7655

200.09 6.7658

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200.11 6.7665

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200.13 6.7672

200.14 6.7675

200.15 6.7679

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200.17 6.7686

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200.20 6.7696

200.21 6.7699

200.22 6.7702

200.23 6.7706

200.24 6.7709

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200.25 6.7713

200.26 6.7716

200.27 6.7719

200.28 6.7723

200.29 6.7726

200.30 6.7729

200.31 6.7733

200.32 6.7736

200.33 6.7740

200.34 6.7743

200.35 6.7746

200.36 6.7750

200.37 6.7753

200.38 6.7757

200.39 6.7760

200.40 6.7763

200.41 6.7767

200.42 6.7770

200.43 6.7773

200.44 6.7777

200.45 6.7780

200.46 6.7784

200.47 6.7787

200.48 6.7790

200.49 6.7794

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200.50 6.7797

200.51 6.7800

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200.53 6.7807

200.54 6.7811

200.55 6.7814

200.56 6.7817

200.57 6.7821

200.58 6.7824

200.59 6.7828

200.60 6.7831

200.61 6.7834

200.62 6.7838

200.63 6.7841

200.64 6.7844

200.65 6.7848

200.66 6.7851

200.67 6.7855

200.68 6.7858

200.69 6.7861

200.70 6.7865

200.71 6.7868

200.72 6.7872

200.73 6.7875

200.74 6.7878

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200.75 6.7882

200.76 6.7885

200.77 6.7888

200.78 6.7892

200.79 6.7895

200.80 6.7899

200.81 6.7902

200.82 6.7905

200.83 6.7909

200.84 6.7912

200.85 6.7915

200.86 6.7919

200.87 6.7922

200.88 6.7926

200.89 6.7929

200.90 6.7932

200.91 6.7936

200.92 6.7939

200.93 6.7943

200.94 6.7946

200.95 6.7949

200.96 6.7953

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200.98 6.7959

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