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Vladimir79 [104]
2 years ago
9

Force F1 acts on a particle and does work W1. Force F2 acts simultaneously on the particle and does work W2. The speed of the pa

rticle does not change. Which one of the following must be true?a. W1 is zero, and W2 is positiveb. W1 = - W2c. W1 is positive, and W2 is positived. W1 is positive, and W2 is zero
Physics
1 answer:
egoroff_w [7]2 years ago
7 0

Answer:

b.) W1 = -W2

Explanation:

According to Newton's third law of motion, action and reaction are equal and opposite. For the particle to maintain a constant speed, it means that the two workdone on the particle are of eqaul magnitude but act in opposite direction. The two weights, instead of adding up annul each other and has no effect on the speed of the particle.

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An astronaut is floating happily outside her spaceship, which is orbiting the earth at a distance above the earths surface equal
serg [7]

Answer:

The astronaut's weight will be one-forth of her normal weight on earth.

Explanation:

From Newton's law of gravitation, we can write the acceleration due to gravity (g) on Earth's surface is given by

g = \dfrac{GM_{e}}{R^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)\\

where 'G' is gravitational constant, 'M_{e}' is Earth's mass and 'R' is Earth's radius.

As shown in the figure, if the astronaut is at a height 'h' from earth's surface and if 'g'' be the value of the acceleration due to gravity at that height, then

g' = \dfrac{G M_{e}}{(R + h)^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Taking the ratio of both the equations, and as given h = R.

\dfrac{g'}{g} &=& \dfrac{g' = \dfrac{G M_{e}}{(R + h)^{2}}}{g' = \dfrac{G M_{e}}{(R + h)^{2}}}\\&=& \dfrac{R^{2}}{(R + h)^{2}}\\&=& R^{2}(R + R)^{2}\\&=& \dfrac{1}{4}\\

So,

&& g' = \dfrac{g}{4}\\&or,& mg' = \dfrac{mg}{4}

where 'm' is the mass of the astronaut.

So the weight of the astronaut will be one-forth her normal weight on earth.

7 0
2 years ago
A bullet is fired horizontally, and at the same instant a second bullet is dropped from the same height. Ignore air resistance.
Brut [27]

Answer:

They hit at the same time

Explanation:

The bullet that is fired horizontally, the horizontal component of the speed is the speed with which is its is fired and the vertical component of the speed comes in picture due to gravity only.

When the bullet is dropped from the same height, the horizontal component is zero but the vertical component arises from the gravity.

The vertical components of the velocity of both the bullets are same and thus, they fall at the same time.

<u>Answer: They hit at the same time</u>

5 0
2 years ago
Which of the following statements about horizons is true?
nalin [4]
<span>All soils have completely different horizon patterns.</span>
6 0
2 years ago
Read 2 more answers
A quarterback throws a football with an initial velocity v at an angle θ above horizontal. Assume the ball leaves the quarterbac
Maru [420]
(a) The y-component or vertical velocity is calculated using:
Vy = Vsin(∅)

(b) The x-component or horizontal velocity is calculated using:
Vx = Vcos(∅)
6 0
2 years ago
Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
horsena [70]

Answer:

a)106.48 x 10⁵ kg.m²

b)144.97 x 10⁵  kgm² s⁻¹  

Explanation:

a)Given

m = 5500 kg

l = 44 m

Moment of inertia of one blade

I= 1/3 x m l²

where m is mass of the blade

l is length of each blade.

Putting all the required values, moment of inertia of one blade will be

I= 1/3 x 5500 x 44²  

I= 35.49 x 10⁵ kg.m²

Moment of inertia of 3 blades

I= 3 x 35.49 x 10⁵ kg.m²

I= 106.48 x 10⁵ kg.m²

b) Angular momentum 'L' is given by

L =I x ω

where,

I= moment of inertia of turbine i.e  106.48 x 10⁵ kg.m²

ω=angular velocity =2π f

f is frequency of rotation of blade i.e  13 rpm

f = 13 rpm=>= 13 / 60 revolution per second

ω = 2π f =>  2π  x  13 / 60 rad / s

L=I x ω =>106.48 x 10⁵ x   2π  x  13 / 60

  = 144.97 x 10⁵  kgm² s⁻¹    

7 0
2 years ago
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