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2 years ago

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A car starting from rest (i.e. initial velocity = 0.0 m/s), moves in the positive X-direction with a constant average accelerati

on = 3.1 m/s2 for 7.9 s. What will be its velocity at that time.

1 answer:

olga_2 [115]2 years ago

8 0

Answer:

Final speed of the car, v = 24.49 m/s

Explanation:

It is given that,

Initial velocity of the car, u = 0

Acceleration, $a=3.1\ m/s^2$

Time taken, t = 7.9 s

We need to find the final velocity of the car. Let it is given by v. It can be calculated using first equation of motion as :

$v=u+at$

$v=0+3.1\times 7.9$

v = 24.49 m/s

So, the final speed of the car is 24.49 m/s. Hence, this is the required solution.

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Answer:

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Explanation:

In the image attached with this answer are shown the given options from which only one is correct.

The correct expression is:

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