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Vedmedyk [2.9K]
1 year ago
8

Which statement accurately describes the motion of the object in the graph above over 10 seconds? Group of answer choices The ob

ject is at rest for 3 seconds and then decreases velocity to 1 cm/s for 3 seconds. The object is at rest for 4 seconds and then moves forward for 4 seconds at 1 cm/s. The object moves forward at 1 cm/s, stops, and then increases velocity to 2 cm/s. The object moves forward at 1 cm/s, stops, and then continues at the same velocity.

Physics
1 answer:
timurjin [86]1 year ago
7 0

Answer:

Object appears to move forward at 1 cm/sec, then the velocity drops to zero for 3 sec and then moves forward at 2 cm/sec     (11 - 3) / (10 - 6) = 2 cm/sec

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an iron rod of length 100m at 10 degree Celsius is used to measure a distance of 2km on a day when the temperature is 40 degree
german

Answer:

0.68 m

Explanation:

α = dL / L1*(dT)

dL = L1(dT) * α

Initial length, L1 = 100

Chang in Length =dL

α linear expansivity ; dL = change in length ; dT = change in temperature ; L1 = initial length

α of iron rod = 1.13 * 10^-5 k

dL = 100(40 - 10) * 1.13 * 10^-5

dL = 100(30) * 1.13 * 10^-5

dL = 3000 * 1.13 * 10^-5

dL = 3390 * 10^-5

dL = 0.0339 m

Error :

Distance measured = 2km = (2 * 1000) = 2000m

[Distance measured / (initial length + change in length)] × change in length

Error = (2000 / (100 + 0.0339)) * 0.0339

Error = (2000 / 100.0339) * 0.0339

Error = 19.993222 * 0.0339

Error = 0.6777702

Error = 0.68 m

4 0
2 years ago
Determine the torque applied to the shaft of a car that transmits 225 hp
Arisa [49]

Incomplete question.The complete question is here

Determine the torque applied to the shaft of a car that transmits 225 hp and rotates at a rate of 3000 rpm.

Answer:

Torque=0.51 Btu

Explanation:

Given Data

Power=225 hp

Revolutions =3000 rpm

To find

T( torque )=?

Solution

As

T(Torque)=\frac{W(Work)}{2\pi n(Revolutions) }

As force moves an object through a distance, work is done on the object. Likewise, when a torque rotates an object through an angle, work is done.

So

T=\frac{225*42.207}{2\pi 3000}\\ T=0.51 Btu

8 0
2 years ago
A measuring cylinder contains 60cm3 of oil at 0 celcius. When a piece of ice was roped into the cylinder it sank completely in o
mariarad [96]

Answer:

S_i=\frac{9}{10} =0.9

Explanation:

Given:

  • volume of oil in the cylinder, V_o=60\ cm^2
  • volume of the oil level when the ice is immersed, V=90\ cm^3
  • the volume level of oil when the ice melted, V'=87\ cm^3

<u>Now, therefore the volume of ice:</u>

V_i=V-V_o

V_i=90-60

V_i=30\ cm^3

<u>Now the volume of water:</u>

V_w=V'-V_o

V_w=87-60

V_w=27\ cm^3

As we know that the relative density is the ratio of density of the substance to the density of water.

<u>So, the relative density of ice:</u>

S_i=\frac{\rho_i}{\rho_w} .....................(1)

as we know that density is given as:

\rm \rho=\frac{mass}{volume}

now eq. (1)

S_i=\frac{m}{V_{i}}\div  \frac{m}{V_w}

where, m = mass of the water or the ice which remains constant in any phase

S_i=\frac{V_w}{V_i}

S_i=\frac{27}{30}

S_i=\frac{9}{10} =0.9

7 0
2 years ago
Is it possible for two pieces of the same metal to have different recrystallization temperatures? Is it possible for recrystalli
Butoxors [25]

Answer:

Explained

Explanation:

Two pieces of the same metal can have different recrystallization temperatures if the pieces  have been cold worked to different amounts. The piece of work cold worked to greater extend will have more internal energy to drive the recrystalline process and lower recrystallization temperature.

Yes, its possible that recrystallization to take place in some regions of a part before it does in other regions of the same part if the work has been unevenly strained or if the part have different thickness at different sections.

6 0
2 years ago
un serbatoio d'acqua di forma cilindrica è riempito con acqua dolce fino a un livello di 6,40 m calcola la pressione dell'acqua
ohaa [14]
Per calcolare la pressione a una certa profondità, devi considerare la legge di Stevino:
<span>p = ρ · g · h

Tenendo conto che:
g = 9,81 m/s²
ρ = 1000 kg/m³

Troviamo:
p(h</span>₁) = ρ · g · h₁ = 1000 · 9,81 · 4,50 = 44145 Pa
p(h₂) = ρ · g · h₂ = 1000 · 9,81 · 5,50 = 53955 Pa


6 0
2 years ago
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