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Zarrin [17]
2 years ago
15

The moon has a mass of 7.4 × 1022 kg and completes an orbit of radius 3.8×108 m about every 28 days. The Earth has a mass of 6 ×

1024 kg and completes an orbit of radius 1.5 × 1011 m every year. What is the speed of the Moon in its orbit? Answer in units of m/s.
Physics
1 answer:
matrenka [14]2 years ago
5 0

To solve this problem it is necessary to apply the kinematic equations of movement description, where the speed of a body is defined as the distance traveled in a given time, that is to say

v = \frac{x}{t}

where,

x = Displacement

t = time

Since the moon is making a path equal to that of a circle, we know by geometry that the perimeter of a circle is given by

x = 2\pi r

x = 2\pi (3.8*10^8)

x=2.39*10^9m

At the same time we have that time is equal to

t = 28days(\frac{86400s}{1day})

t = 2419200s

Using the equation for velocity we have finally that

v= \frac{x}{t}

v = \frac{2.39*10^9}{2419200}

v = 987.92 m/s

Therefore the speed of the Moon in its orbit is 987.92m/s

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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
2 years ago
Suppose you are myopic (nearsighted). You can clearly focus on objects that are as far away as 52.5 cm away. You can clearly foc
Lilit [14]

Answer:

Explanation:

Image of distant object will be made at far point or at 52.5 so

object distance u = infinity

image distance v = - 52.5 cm

focal length required = f

Lens formula

1 / v - 1 / u = 1 / f

1 /  - 52.5 - 0 = 1 / f

f =  -52.5 cm

= -.525 m

Power P = 1 / f = -  1 / .525

= -  1.90

now , for eye with glass we shall find new near point .

v = ?

u = - 17.2 cm

f = -  52.5 cm

1 / v - 1 / u = 1 / f

  1 / v + 1 / 17.2 = -  1 / 52.5

1 / v  = - 1 / 17.2 -    1 / 52.5

= - .05813 -  .019

= - .07713

u = - 12.96 cm

so new near point will be 12.96 cm

5 0
1 year ago
Match each type of consequence with its resulting behavior change
ira [324]

Answer:

Janet stops parking in handicapped spaces after she gets a big parking ticket. - Positive Punishment

Peter’s recess is taken away to discourage him from getting into fights with the other children. - Negative Punishment

Ted increases paying his bills on time to avoid a late fee. - Negative Reinforcement

Sally increases the amount of work she completes to receive more pay. - Positive Reinforcement

Explanation:

In operant conditioning, the main principle is that behavior increases or decreases its frequency depending on whether it's reinforced or punished. A behavior can be reinforced by giving something the subject appreciates, like more pay for their work (positive reinforcement) or taking away something they dislike, like late fees (negative reinforcement). Punishments work the same way, you can give something the subject dislikes, like a parking ticket, (positive punishment) or taking away something they like recess for a child. (negative punishment).

5 0
1 year ago
An aircraft on it's take-off run has a steady acceleration of 3m/s^2. How much velocity does it gain 10 seconds?
cluponka [151]
Acceleration measures how fast the speed changes over time.

So, over 10s, the aircraft's speed changes by 3\frac{m}{ s^{2} } * 10s

So, the change is 30\frac{m}{s}

Note that the one of the second units cancels out in the answer.
6 0
1 year ago
Read 2 more answers
Water waves in a small tank are .06 m long. They pass a given point at a rate of 14.8 waves every three seconds. What is the spe
snow_lady [41]

Answer:

Speed = 0.296m/2

Period = 0.203 s

Explanation:

If by 'long' you mean the wavelength of the waves, then the wavelength \lambda=0.06m.

The frequency f of the waves is 14.8 waves every 3 seconds or

f=14.8/3 =4.33Hz.

Now the relationship between wavelength \lambda, frequency f and speed v of the waves is:

v=\lambda f

We put in the values \lambda=0.06m and f=4.933Hz and get:

\boxed{v=0.06*4.922=0.296m/s}

Now the period T is just the inverse of the frequency, or

T=\frac{1}{f}

\boxed{T=\frac{1}{4.933}=0.203\:seconds }

4 0
1 year ago
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