A rock is thrown horizontally at a speed of 5.0 m/s from the top of a cliff 64.7 m high. The rock hits the ground 18.0 m from th
e base of the cliff. How would this distance change if the rock was thrown at 10.0 m/s?
2 answers:
Refer to the diagram shown.
Assume g = 9.8 m/s² and ignore air resistance
When the rock is launched from a height of 64.7 m,
u = 5.0 m/s, the horizontal velocity
v = 0, the initial vertical velocity
If the rock hits the ground 18.0 m from the base of the cliff, then the time of flight is
t = (18.0 m)/(5.0 m/s) = 3.6 s
The vertical distance traveled is
s = (1/2)*(9.8 m/s²)*(3.6 s)² = 63.504 m
Because this distance is less than 64.7 m, ground level is slightly higher away from the base of the cliff. It is higher by
64.7 - 63.504 = 1.196 m
If the rock is thrown at 10 m/s, the time of flight remains the same because acceleration due to gravity is the same.
Therefore the horizontal distance traveled is
(10.0 m/s)*(3.6 s) = 36.0 m
Answer: The distance will be 36.0 m
Assume g = 9.8 m/s² and ignore air resistance
When the rock is launched from a height of 64.7 m,
u = 5.0 m/s, the horizontal velocity
v = 0, the initial vertical velocity
If the rock hits the ground 18.0 m from the base of the cliff, then the time of flight is
t = (18.0 m)/(5.0 m/s) = 3.6 s
The vertical distance traveled is
s = (1/2)*(9.8 m/s²)*(3.6 s)² = 63.504 m
Because this distance is less than 64.7 m, ground level is slightly higher away from the base of the cliff. It is higher by
64.7 - 63.504 = 1.196 m
If the rock is thrown at 10 m/s, the time of flight remains the same because acceleration due to gravity is the same.
Therefore the horizontal distance traveled is
(10.0 m/s)*(3.6 s) = 36.0 m
Answer: The distance will be 36.0 m
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Answer:
B. The distance between the slits and the screen is halved.
C. The slit width is doubled.
D. A green, rather than red, light source is used.
E. The experiment is conducted in a water-filled tank.
Explanation:
As we know that the position of first minimum is given as
so we have
so width of minimum is given as
now if we need to decrease the angular position of minimum
1). so we can decrease the distance of screen from the slit
2). we can decrease the wavelength
3). We can increase the width of the slit
So correct answer will be
B. The distance between the slits and the screen is halved.
C. The slit width is doubled.
D. A green, rather than red, light source is used.
E. The experiment is conducted in a water-filled tank.
Answer: m= 35.6 kg
Explanation:
For finding the mass of the stone we have the formula
v=
Here, Tension= m*g = m*9.81
and linear mass density=
Linear mass density=
Linear mass density= 0.0127 kg/m
Velocity=
Velocity= 2 *
Velocity= 165.8 m/s
So putting all these values in equation we get
v=
165.8=
Solving we get
m= 35.58 kg
or m= 35.6 kg
Answer:
Statement 1) False
Statement 2) False
Statement 3) True
Explanation:
The uncertainty principle states that " in a physical system certain quantities cannot be measured with random precision no matter whatever the least count of the instrument is" or we can say while measuring simultaneously the position and momentum of a particle the error involved is
Thus if we measure x component of momentum of a particle with 100% precision we cannot measure it's position 100% accurately as the error will be always there.
Statement 1 is false since measurement of x and y positions has no relation to uncertainty.
Statement 2 is false as both the momentum components can be measured with 100% precision.
Statement 3 is true as as demanded by uncertainty principle since they are along same co-ordinates.