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melisa1 [442]
2 years ago
11

Traffic noise on Beethoven Boulevard has an intensity level of 80 dB; the traffic noise on Mozart Alley is only 60 dB. Part A Co

mpared to the sound intensity on Beethoven Boulevard, the sound intensity on Mozart Alley is Compared to the sound intensity on Beethoven Boulevard, the sound intensity on Mozart Alley is a. 25% lower.b. 100 times lower. c. 20 W/m2 lower. d. 20 times lower.
Physics
1 answer:
uranmaximum [27]2 years ago
8 0

Answer:

option (b)

Explanation:

Io = 10^-12 w/m^2

In Case I:

dB = 80 dB

The formula for the intensity of sound

dB=10log\left ( \frac{I}{I_{0}} \right )

80=10log\left ( \frac{I_{1}}{I_{0}} \right )

I_{1} = 10^{8}\times I_{0}

I_{1} = 10^{8}\times 10^{-12}=10^{-4}W/m^{2}   ... (1)

In Case II:

dB = 60 dB

The formula for the intensity of sound

dB=10log\left ( \frac{I_{2}}{I_{0}} \right )

60=10log\left ( \frac{I_{2}}{I_{0}} \right )

I_{2} = 10^{6}\times I_{0}

I_{2} = 10^{6}\times 10^{-12}=10^{-6}W/m^{2}   ... (2)

So, by equation 2 and 1 we get

I_{2}=\frac{I_{1}}{100}

Thus, the intensity of sound is 100 times lower.

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Question
nataly862011 [7]

The density of a material is constant and it is given by the ratio of the mass to the volume of the material

The mass of the liquid and the full bottle ae

The mass of the liquid is <u>450 g</u>

The mass of the filled bottle is <u>530 grams</u>

<u></u>

The reason the above values are correct are as follows:

The given parameters are;

Volume of the bottle, V = Half litre

Mass of the bottle, m_b = 80 g

The volume of liquid in the bottle when filled, V = 500 cm³

The density of the olive oil with which the bottle is filled, ρ = 0.9 g/cm³

a. Required:

To calculate the mass of oil in the bottle

Solution:

The volume of oil in the bottle when the bottle is filled, V = 500 cm³

Density, \ \rho = \dfrac{Mass}{Volume}  = \dfrac{m}{V}

The mass of the liquid, m = ρ × V

∴ m = 0.9 g/cm³ × 500 cm³ = 450 g

The mass of the liquid, m = <u>450 g</u>

<u></u>

b. The mass of the oil in the bottle, m = grams

The mass of the full bottle, m_{filled} = m + m_b

∴ m_{filled} = 450 g + 80 g = 530 g

The mass of the full bottle, m_{filled} = <u>530 grams</u>

Learn more about density here:

brainly.com/question/18110802

4 0
1 year ago
A 0.0140 kg bullet traveling at 205 m/s east hits a motionless 1.80 kg block and bounces off it, retracing its original path wit
makvit [3.9K]

Answer:

Final velocity of the block = 2.40 m/s east.

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum

Mass of bullet = 0.0140 kg

Consider east as positive.

Initial velocity of bullet = 205 m/s

Mass of Block = 1.8 kg

Initial velocity of block = 0 m/s

Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s

Final velocity of bullet = -103 m/s

We need to find final velocity of the block( u )

Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u

We have

            2.87 = -1.442 + 1.8 u

               u = 2.40 m/s

Final velocity of the block = 2.40 m/s east.

7 0
2 years ago
Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller
jeka94

Answer:

Explanation:

Torque on smaller wheel

= F x r

50 x .30

= 15 Nm

Torque on larger wheel

= F x .5

For equilibrium

F x .5 = 15

F = 15 / .5

= 30 N

8 0
2 years ago
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to
erastovalidia [21]
Would presume you are asked to find the volume, since there is no second volume.

By General Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

1.6 * 168 /255 = 1.3*V₂/285

V₂ = 1.6 * 168 * 285 / (1.3*255)

V₂ = 231.095

Final volume ≈ 231 cm³
7 0
2 years ago
Read 2 more answers
A hot air balloon of total mass M (including passengers and luggage) is moving with a downward acceleration of magnitude a. As i
LUCKY_DIMON [66]

Answer:

The fraction of mass that was thrown out is calculated by the following Formula:

M - m = (3a/2)/(g²- (a²/2) - (ag/2))

Explanation:

We know that Force on a moving object is equal to the product of its mass and acceleration given as:

F = ma

And there is gravitational force always acting on an object in the downward direction which is equal to g = 9.8 ms⁻²

Here as a convention we will use positive sign with acceleration to represent downward acceleration and negative sign with acceleration represent upward acceleration.

Case 1:

Hot balloon of mass = M

acceleration = a

Upward force due to hot air = F = constant

Gravitational force downwards = Mg

Net force on balloon is given as:

Ma = Gravitational force - Upward Force                              

Ma = Mg - F                      (balloon is moving downwards so Mg > F)

F = Mg - Ma

F = M (g-a)

M = F/(g-a)

Case 2:

After the ballast has thrown out,the new mass is m. The new acceleration is -a/2 in the upward direction:

Net Force is given as:

-m(a/2) = mg - F        (Balloon is moving upwards so F > mg)

F = mg + m(a/2)

F = m(g + (a/2))

m = F/(g + (a/2))

Calculating the fraction of the initial mass dropped:

M-m = \frac{F}{g-a} - \frac{F}{g+\frac{a}{2} }\\M-m = F*[\frac{1}{g-a} - \frac{1}{g+\frac{a}{2} }]\\M-m = F*[\frac{(g+(a/2)) - (g-a)}{(g-a)(g+(a/2))} ]\\M-m = F*[\frac{g+(a/2) - g + a)}{(g-a)(g+(a/2))} ]\\M-m = F*[\frac{(3a/2)}{g^{2}-\frac{a^{2}}{2}-\frac{ag}{2}} ]

5 0
2 years ago
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