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melisa1 [442]
2 years ago
11

Traffic noise on Beethoven Boulevard has an intensity level of 80 dB; the traffic noise on Mozart Alley is only 60 dB. Part A Co

mpared to the sound intensity on Beethoven Boulevard, the sound intensity on Mozart Alley is Compared to the sound intensity on Beethoven Boulevard, the sound intensity on Mozart Alley is a. 25% lower.b. 100 times lower. c. 20 W/m2 lower. d. 20 times lower.
Physics
1 answer:
uranmaximum [27]2 years ago
8 0

Answer:

option (b)

Explanation:

Io = 10^-12 w/m^2

In Case I:

dB = 80 dB

The formula for the intensity of sound

dB=10log\left ( \frac{I}{I_{0}} \right )

80=10log\left ( \frac{I_{1}}{I_{0}} \right )

I_{1} = 10^{8}\times I_{0}

I_{1} = 10^{8}\times 10^{-12}=10^{-4}W/m^{2}   ... (1)

In Case II:

dB = 60 dB

The formula for the intensity of sound

dB=10log\left ( \frac{I_{2}}{I_{0}} \right )

60=10log\left ( \frac{I_{2}}{I_{0}} \right )

I_{2} = 10^{6}\times I_{0}

I_{2} = 10^{6}\times 10^{-12}=10^{-6}W/m^{2}   ... (2)

So, by equation 2 and 1 we get

I_{2}=\frac{I_{1}}{100}

Thus, the intensity of sound is 100 times lower.

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Which of the following equations illustrates the law of conservation of matter?
AlladinOne [14]

Answer: The correct answer is option (B).

Explanation:

Law of conservation of mass: 'In a chemical reaction, mass neither be created nor be destroyed'

In the balance chemical equation,total mass of the reactants is equal to the total mass of the products.

A. 2Na+Cl_2\rightarrow  NaCl

[2\times (23 g/mol)+(35.5 g/mol)\times 2]=[23 g/mol+35.5 g/mol]

117 g/mol  ≠ 58.5 g/mol

Law of Conservation of Mass not followed.

B.2Na+Cl_2\rightarrow 2NaCl

[2\times (23 g/mol)+(35.5 g/mol)\times 2]=2\times [23 g/mol+35.5 g/mol]

117 g/mol  =  117 g/mol

Law of Conservation of Mass is followed.

C.2Na+2Cl_2\rightarrow 2NaCl

[2\times (23 g/mol)+(35.5 g/mol)\times 2]=2\times [23 g/mol+35.5 g/mol]

188 g/mol  ≠ 117 g/mol

Law of Conservation of Mass not followed.

D.Na+Cl_2\rightarrow 2NaCl

[(23 g/mol)+(35.5 g/mol)\times 2]=2\times [23 g/mol+35.5 g/mol]

94 g/mol  ≠ 117 g/mol

Law of Conservation of Mass not followed.

Hence, the correct answer is option (B).

5 0
2 years ago
Suppose that a rectangular toroid has 2,000 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
andrey2020 [161]

Answer:

0.01154 A

Explanation:

We have given the energy in the magnetic field U=4\times 10^{-6}J

Value of inductance L =0.060 H

Energy stored in magnetic field is given by U=\frac{1}{2}Li^2

i=\sqrt{\frac{2U}{L}}

i=\sqrt{\frac{2\times 4\times 10^{-6}}{0.06}}=0.01154\ A

So the current flowing through rectangular toroid will be 0.01154 A

3 0
2 years ago
Which of the following relationships must be true according to the laws of series and parallel connections? (Select only relatio
tester [92]

Answer:

Explanation:

a False

b True

c True

d False

e False

f False

g True

h False

i False

4 0
2 years ago
D=? V=100mL M=1.5kg=___g
Nana76 [90]
If you go to a website known as 'Wolfram' and type in the question they should be able to answer it.  It's basically a very smart calculator.  I'd add a link but I don't want to seem like I'm advertising, and it's against Brainly rules.
8 0
2 years ago
Among the largest passenger ships currently in use, the Norway has been in service the longest. The Norway is more than 300 m lo
LenaWriter [7]

Answer:

6.33\times 10^8\ kg\cdot m/s

Explanation:

Mass of the ship (m) = 6.9 × 10⁷ kg

Speed of the ship (v) = 33 km/h

First, let us convert the speed from km/h to m/s using the conversion factor.

We know that, 1 km/h = 5/18 m/s

So, 33 km/h = 33\times \frac{5}{18}=9.17\ m/s

Now, we know, the momentum of an object only depends on its mass and speed. Momentum is independent of the length of the object.

So, here, length of the ship doesn't play any role in the determination of the momentum.

Magnitude of momentum of the ship = Mass × Speed

                                                             = (6.9\times 10^7\ kg)(9.17\ m/s)

                                                             = 6.33\times 10^8\ kg\cdot m/s

Therefore, the magnitude of ship's momentum is 6.33\times 10^8\ kg\cdot m/s.

6 0
2 years ago
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