Answer:
See the explanation below
Explanation:
To better understand this problem, a cylinder sketch is attached before and after the cut, we see that after the cut, the shape of this resembles that of a right triangle.
We can find, the centroid in the xy plane, knowing that the centroid for a triangle is located a third of its base.
In the z axis there is no displacement of the centroid.
The static friction exerted on the block by the incline is
.
The given parameters;
- <em>mass of the block, = M</em>
- <em>coefficient of static friction in section 1, = </em>
<em /> - <em>angle of inclination of the plane, = θ</em>
<em />
The normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;

Thus, the static friction exerted on the block by the incline is 
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The answer is 96 N .....................................
To solve this problem it is necessary to use the given proportions of power and energy, as well as the energy conversion factor in Jules to Calories.
The power is defined as the amount of energy lost per second and whose unit is Watt. Therefore the energy loss rate given in seconds was


The rate of energy loss per day would then be,


That is to say that Energy in Jules per lost day is 5356800J
By definition we know that 
In this way the energy in Cal is,


The number of kilocalories (food calories) must be 1279.694 KCal
The question above can be answered through using the concept of Conservation of Momentum which may be expressed as,
m1v1 + m2v2 = mTvT
where m1 and v1 are mass and initial velocity of Tex, 2s are that of the bull, and the Ts are the total. Then substituting,
(85 kg)(3 m/s) + (520 kg)(13 m/s) = (520 + 85)(vT)
The value of vT obtained from above equation is 11.6 m/s