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Andru [333]
2 years ago
12

A professional driver drove a long linear route at an average speed of 30 miles per hour. Immediately after completing this driv

e, the driver turned around drove back on the same route at an average speed of 70 miles per hour. If the round trip took 2 hours, how many miles long is this route?
Physics
2 answers:
Lady_Fox [76]2 years ago
8 0

Answer:

84 miles long is the route

Explanation:

Let the distance is d

It is given that driver drove his car with 30 miles per hour

So time t=\frac{d}{30}

And when he return his velocity is 70 miles per hour

So time t=\frac{d}{370

We know that average speed =\frac{total\ distance}{total\ time}=\frac{2d}{\frac{d}{30}+\frac{d}{70}}=42m/sec

Total time of the trip is given as 2 hour

So total distance = total time × average speed = 42×2 = 84 miles

notsponge [240]2 years ago
4 0

Answer:

The route was 42 miles long.

Explanation:

Let the distance covered from starting point to end point be x.

Average speed of the car = 30 mile/hour

Time taken to cover x distance = t

t=\frac{x}{30 mile/hr}

The distance covered from end point point to starting point back = x

Average speed of the car = 70 mile/hour

Time taken to cover x distance = t'

t'=\frac{x}{70 mile/hr}

Average speed of the car:

\frac{x+x}{t+t'}=\frac{2x}{\frac{x}{30 mile/hr}+\frac{x}{70 mile/hr}}=42 mile/hour

Total time taken in round trip  = 2 hours

\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}

42 mile/hr=\frac{\text{Total distance}}{2 hr}

Total distance covered by car= 42 mile/hr × 2 hr = 84 miles

Distance of the route = 84 ÷ 2 = 42 mile

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A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational
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Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

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Pebble: F = 29.44N

(b)Calculate the magnitude of the acceleration of each object when released.

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Pebble:  a =9.8m/s^{2}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{m1m2}{r^{2}}  (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

<em>Case for the rock </em>m = 5.0 Kg<em>:</em>

m1 will be equal to the mass of the Earth m1 = 5.972×10^{24} Kg and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth r = 6371000m.

F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(5.0 Kg)}{(6371000 m)^{2}}

F = 49.06N

Newton's second law can be used to know the acceleration.

F = ma

a =\frac{F}{m} (2)

a =\frac{(49.06 Kg.m/s^{2})}{(5.0 Kg)}

a =9.8m/s^{2}

<em>Case for the pebble </em>m = 3.0 Kg<em>:</em>

F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(3.0 Kg)}{(6371000 m)^{2}}

F = 29.44N

a =\frac{F}{m}

a =\frac{(29.44 Kg.m/s^{2})}{(3.0 Kg)}

a =9.8m/s^{2}

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A rectangular block weighs 240 N. the area of the block in contact with the floor is 20 cm2.calculate the pressure on the floor(
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Answer:

12 N/cm²

Explanation:

From the question given above, the following data were obtained:

Weight (W) of block = 240 N

Area (A) = 20 cm²

Pressure (P) =?

Next, we shall determine the force exerted by the block. This can be obtained as follow:

Weight (W) of block = 240 N

Force (F) =.?

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