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Andru [333]
2 years ago
12

A professional driver drove a long linear route at an average speed of 30 miles per hour. Immediately after completing this driv

e, the driver turned around drove back on the same route at an average speed of 70 miles per hour. If the round trip took 2 hours, how many miles long is this route?
Physics
2 answers:
Lady_Fox [76]2 years ago
8 0

Answer:

84 miles long is the route

Explanation:

Let the distance is d

It is given that driver drove his car with 30 miles per hour

So time t=\frac{d}{30}

And when he return his velocity is 70 miles per hour

So time t=\frac{d}{370

We know that average speed =\frac{total\ distance}{total\ time}=\frac{2d}{\frac{d}{30}+\frac{d}{70}}=42m/sec

Total time of the trip is given as 2 hour

So total distance = total time × average speed = 42×2 = 84 miles

notsponge [240]2 years ago
4 0

Answer:

The route was 42 miles long.

Explanation:

Let the distance covered from starting point to end point be x.

Average speed of the car = 30 mile/hour

Time taken to cover x distance = t

t=\frac{x}{30 mile/hr}

The distance covered from end point point to starting point back = x

Average speed of the car = 70 mile/hour

Time taken to cover x distance = t'

t'=\frac{x}{70 mile/hr}

Average speed of the car:

\frac{x+x}{t+t'}=\frac{2x}{\frac{x}{30 mile/hr}+\frac{x}{70 mile/hr}}=42 mile/hour

Total time taken in round trip  = 2 hours

\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}

42 mile/hr=\frac{\text{Total distance}}{2 hr}

Total distance covered by car= 42 mile/hr × 2 hr = 84 miles

Distance of the route = 84 ÷ 2 = 42 mile

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b) v=9.8m/s

c) \beta =-35.46º

Explanation:

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c) The <u><em>direction of the ball</em></u> is:

\beta=tan^{-1}(\frac{v_{y} }{v_{x}})=tan^{-1}(\frac{-5.7}{8})=-35.46º

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