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Darya [45]
2 years ago
8

Why does carpet tend to produce differences in static electricity more that hardwood or tile floors

Physics
1 answer:
Makovka662 [10]2 years ago
4 0

Answer:

This is because the rubbing releases negative charges, called electrons, which can build up on one object to produce a static charge. For example, when you shuffle your feet across a carpet, electrons can transfer onto you, building up a static charge on your skin.

Explanation:

This is because the rubbing releases negative charges

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Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
babunello [35]

Answer:

Separation increases at all times that rock X falls because it falls with a greater speed

Explanation:

For both rocks, let initial velocity ∪=0

To find the displacement at any given time interval of Δt then

S= ∪Δt +0.5gΔt²

Since rock X is first released followed by Y, then X has a greater speed than Y therefore the distance covered by X is longer. This is because despite 0.5gΔt² being same for both rocks at any time Δt but rock X having already attained some velocity, its ∪Δt  is more hence the separation S increases. Conclusively, S increases at all times that rock X falls since rock X falls with a greater velocity than rock Y

7 0
2 years ago
A skier is moving down a snowy hill with an acceleration of 0.40 m/s2. The angle of the slope is 5.0∘ to the horizontal. What is
kirill115 [55]

Answer:

1.25377 m/s²

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

\mu = Coefficient of friction

\theta = Slope

From Newton's second law

mgsin\theta-f=ma\\\Rightarrow mgsin\theta-\mu mgcos\theta=ma\\\Rightarrow \mu=\frac{gsin\theta-a}{gcos\theta}\\\Rightarrow \mu=\frac{9.81\times sin5-0.4}{9.81\times cos5}\\\Rightarrow \mu=0.04655

Applying \mu to the above equation and \theta=10^{\circ}

mgsin\theta-\mu mgcos\theta=ma\\\Rightarrow a=gsin\theta-\mu gcos\theta\\\Rightarrow a=9.81\times sin10-0.04655\times 9.81\times cos10\\\Rightarrow a=1.25377\ m/s^2

The acceleration of the same skier when she is moving down a hill is 1.25377 m/s²

3 0
2 years ago
Suppose you increase your walking speed from 1 m/s to 3 m/s in a period of 1 s. What is your acceleration?
Effectus [21]

Answer:

2 m/s²

Explanation:

a = Δv / Δt

a = (3 m/s − 1 m/s) / 1 s

a = 2 m/s²

5 0
2 years ago
Use scientific (exponential) notation to express the following quantities in terms of the SI base units in
Anna007 [38]

Answer:

When a number is written in scientific notation (representing the number using powers of base ten) it is expressed so that it contains a digit in the place of the units and all other digits after the decimal point, multiplied by the respective exponent.  For example, the number 4.232(10)^{3}.

On the other hand, it is known the units in the SI for mass, length, time and temperature are kilogram (kg), meter (m), second (s) and Kelvin (K), respectively. In addition, thera are prefixes of the International System (SI) that indicate a specific factor of 10.

For example:

-Giga (G) is a prefix that indicates a factor of 10^{6}

-Pico (p) is a prefix that indicates a factor of 10^{-12}

-Mili (m) is a prefix that indicates a factor of 10^{-3}

-Micro (\mu) is a prefix that indicates a factor of 10^{-6}

-Tera (T) is a prefix that indicates a factor of 10^{12}

-Kilo (K) is a prefix that indicates a factor of 10^{3}

Knowing this, let's express these quantities in terms of the SI base units:

0.13 g=0.00013 kg=1.3 (10)^{-4}kg

232 Gg=232(10)^{6}g=232 (10)^{3}kg

5.23 pm=5.23(10)^{-12}m

86.3 mg=86.3(10)^{-3}g=8.63 (10)^{-5}kg

37.6 cm=0.376 m=3.76 (10)^{-1}m

54 \mu m=54 (10)^{-6}m

1 Ts=1 (10)^{-12}s

27 ps=27 (10)^{-12}s

0.15 mK=0.15(10)^{-3}K

8 0
2 years ago
cicadas produce a sound that has a frequency of 123 Hz. what is the wavelength of this sound in the air? the speed of sound in a
mojhsa [17]

Answer: 2.72 metres

Explanation:

Given that:

frequency of sound F = 123 Hz. wavelength of sound in the air = ?

speed of sound in air V = 334 m/s

Recall that wavelength is the distance covered by the wave after one complete cycle. It is measured in metres, and represented by the symbol λ.

So, apply V = F λ

λ = V /F

λ = 334m/s / 123Hz

λ = 2.72m

Thus, the wavelength of this sound in the air is 2.72 metres

4 0
2 years ago
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