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2 years ago

15

A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he

slows to 3 m/s in 1 minute. What is the cyclist’s acceleration?
–0.08 m/s2
0.08 m/s2
–12 m/s2
12 m/s2

2 answers:

taurus [48]2 years ago

7 0

-3 m/s
---------
per min

oh I think 8m/s to 3m/s to 0m/s

idk probably -0.08

maxonik [38]2 years ago

6 0

The answer is -0.08m/s²

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The Earth's tilt does cause the seasons but the distance from the sun and has nothing to do with the change in seasons. In June, when the Northern Hemisphere is tilted in the direction of the Sun during the Northern Hemisphere summer the Earth is actually farthest from the Sun. In January, when the Southern Hemisphere is tilted in the direction of the Sun during the Northern Hemisphere winter the Earth is actually closest to the Sun. This is caused due to the elliptical orbit of the Earth. So, distance of Earth from the Sun has nothing to do with the seasons.

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A small box of mass m1 is sitting on a board of mass m2 and length L (Figure 1) . The board rests on a frictionless horizontal s

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Explanation:

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Pions have a half-life of 1.8 x 10^-8 s. A pion beam leaves an accelerator at a speed of 0.8c. What is the expected distance ove

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Answer:

the expected distance is 4.32 m

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given data

half life time = 1.8 × $10^{-8}$ s

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to find out

expected distance over

solution

we know c is speed of light in air is 3 × $10^{8}$ m/s

we calculate expected distance by given formula that is

expected distance = half life time × speed .........1

put here all these value

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2 years ago

You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of 630 km above the planet's surfac

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Answer:

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Explanation:

Step 1: Data given

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⇒ with v= the ship's orbal speed = 4900 m/S

⇒ with R = the radius of the planet = 4.48 *10^6 m

⇒ with h = the distance above the planet's surface = 630000 meter

g = (4900² * ( 4.48*10^6+ 630000)) / ((4.48*10^6)²)

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<u>Step 3:</u> Describe the position of the projectile

Horizontal component: x(t) = v0*t *cos∅

Vertical component: y(t) = v0*t *sin∅ -1/2 gt² ( will be reduced to 0 in time )

⇒ with ∅ = 30.8 °

⇒ with v0 = 13.6 m/s

⇒ with t= v(sin∅)/g = 1.14 s

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Horizontal range d =26.63 m

The horizontal range of the projectile = 26.63 meters

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