Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
1 answer:
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Answer:
string's damping is 1.03676
Explanation:
given data
sound level = 9.0 dB
time = 1 sec
to find out
string's damping
solution
we will apply here formula for string damping (b) that is
A(t) = A × ...................1
we know here I ∝ A² so
√I(t) = √I ×
√I(t) / √I = .....................2
we know sound level decreases 9 dB i.e ΔdB = 9
so we can write
ΔdB = 10 log ( I(t) / I)
9 = 10 log ( I(t) / I)
I(t) / I =
I(t) / I = 0.1258
and
√I(t) / I) = √0.1258 = 0.3546 .......................3
from equation 2 and 3 we get
0.3546 =
take ln both side
-bt = ln 0.3546
here we know t is 1 sec
so
- b = - 1.03676
b = 1.03676
so here string's damping is 1.03676
Answer:
So instantaneous velocity after 9 sec will be 88.2 m/sec
Explanation:
We have given time t = 9 sec
As the object is released from rest so its initial velocity u = 0 m/sec
We have to find its final velocity v
Acceleration due to gravity
From first equation of motion we know that
So instantaneous velocity after 9 sec will be 88.2 m/sec