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Citrus2011 [14]
2 years ago
5

1. If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released. It will oscillate. I

f is displaced 0.120m from its equilibrium position and released with zero initial speed, then after 0.800s its displacement is found to be 0.120m on the opposite side, and it has passed the equilibrium position once during this interval. Find, a) the amplitude; b) the period; c) the frequency.
Physics
1 answer:
AURORKA [14]2 years ago
3 0

Answer: a) 0.12m; b) 1,6 s; c) 0.625 1/s

Explanation: The simple harmonic movement can be described by a sin or cosine function  in time.

This can be in the form:

X(t)= A Sin/Cos (wt+φ) where φ is initial phase o position at t=0

w the angular frequency are related to the frequency (f) as 2Pif

and f=1/T period of oscillating

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Two friends of different masses are on the playground. They are playing on the seesaw and are able to balance it even though the
Westkost [7]

Answer:

They are able to balance torques due to gravity.

F_1 L_1 = F_2L_2

Explanation:

When two friends of different masses will balance themselves on see saw then at equilibrium position the see saw will remain horizontal

This condition will be torque equilibrium position where the see saw will not rotate

Here we can say

F_1 L_1 = F_2L_2

here we know that force is due to weight of two friends

and their positions are different with respect to the lever about which see saw is rotating

since both friends are of different weight so they will balance themselves are different positions as per above equation

5 0
2 years ago
A professor's office door is 0.89 m wide, 2.0 m high, and 4.0 cm thick; has a mass of 25 kg ; and pivots on frictionless hinges.
taurus [48]
In order to answer this question ... strange as it may seem ...
we only need one of those measurements that you gave us
that describe the door.

The door is hanging on frictionless hinges, and there's a torque
being applied to it that's trying to close it.  All we need to do is apply
an equal torque in the opposite direction, and the door doesn't move.

Obviously, in order for our force to have the most effect, we want
to hold the door at the outer edge, farthest from the hinges.  That
distance from the hinges is the width of the door ... 0.89 m.

We need to come up with 4.9 N-m of torque,
applied against the mechanical door-closer.

Torque is (force) x (distance from the hinge).

                                    4.9 N-m  =  (force) x (0.89 m) 

Divide each side by 0.89m:    Force = (4.9 N-m) / (0.89 m)

                                                             =  5.506 N .
7 0
2 years ago
An athlete stretches a spring an extra 40.0 cm beyond its initial length. how much energy has he transferred to the spring, if t
marissa [1.9K]
The energy transferred to the spring is given by:
U= \frac{1}{2}kx^2
where 
k is the spring constant
x is the elongation of the spring with respect its initial length

Let's convert the data into the SI units:
k=52.9 N/cm = 5290 N/m
x=40.0 cm=0.4 m

so now we can use these data inside the equation ,to find the energy transferred to the spring:
U= \frac{1}{2}kx^2= \frac{1}{2}(5290 N/m)(0.4m)^2=423.2 J
4 0
2 years ago
The gravity tractor is a proposed spacecraft that will fly close to an asteroid whose trajectory threatens to impact the Earth.
Talja [164]

Answer:

F_g=461lb_f

Explanation:

First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.

If r = d/2 = 645ft, then:

V = \frac{4}{3} \pi r^3

V = 1.124*10^{9}ft^3

So

\delta_{iron}=m/V=491lb/ft^3

m=V*\delta=5.519*10^{11}lb

Once you  know both masses, you can calculate the force using Newton's universal law of gravitation:

F_g=G\frac{m_1m_2}{d^2}

Where G is the gravitational constant:

G= 1.068846 * 10^{-9} ft^3 lb^{-1} s^{-2}

F_g=461lb_f

4 0
2 years ago
A steel aircraft carrier is 370 m long when moving through the icy North Atlantic at a temperature of 2.0 °C. By how much does t
34kurt

Answer:

The carrier lengthen is 0.08436 m.

Explanation:

Given that,

Length = 370 m

Initial temperature = 2.0°C

Final temperature = 21°C

We need to calculate the change temperature

Using formula of change of temperature

\Delta T=T_{f}-T_{i}

\Delta T=21-2.0

\Delta T=19^{\circ}C

We need to calculate the carrier lengthen

Using formula of length

\Delta L=\alpha_{steel}\times L_{0}\times\Delta T

Put the value into the formula

\Delta L=1.2\times10^{-5}\times370\times19

\Delta L=0.08436\ m

Hence, The carrier lengthen is 0.08436 m.

8 0
2 years ago
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