the normal force is the force applied opposite to the weight
of the was box. So the normal force is equal to the weight of the box = 24 kg
*(9.81 m/s2) = 235.44 N
the acceleration of the box be solve using newtons 2nd
law of motion:
F = ma
a = F/ m = 585 N/ 24 kg = 24.38 m/s2
For the answer tot he questions above, I know this one.
The answers are
<span>-sets 2-3 hours after the sun sets - waxing crescent
-occurs about 3 days before the new moon - waning crescent
-occurs 14 days after the new moon - full moon
-rises at about the time the sun sets - full moon
-visible due south at midnight - full moon
-visible near eastern horizon just before sunrise waning crescent
-visible near western horizon about an hour after sunset waxing crescent</span>
Complete Question
The complete question is shown on the first uploaded image
Answer:
The angle between shuttle's velocity and the Earth's field is 
Explanation:
From the question we are told that
The length of eire let out is 
The emf generated is 
The earth magnetic field is 
The speed of the shuttle and tether is 
The emf generated is mathematically represented as

making
the subject of the formula
![\theta = sin ^{-1}[ \frac{\epsilon}{L * B *v} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%20sin%20%5E%7B-1%7D%5B%20%5Cfrac%7B%5Cepsilon%7D%7BL%20%20%2A%20B%20%20%2Av%7D%20%5D)
substituting values
![\theta = sin ^{-1}[ \frac{40}{250 * (5*10^{-5}) *(7.80 *10^{3})} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%20sin%20%5E%7B-1%7D%5B%20%5Cfrac%7B40%7D%7B250%20%20%2A%20%285%2A10%5E%7B-5%7D%29%20%20%2A%287.80%20%2A10%5E%7B3%7D%29%7D%20%5D)

Complete Question
In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
Answer:
The speed of the helicopter is 
Explanation:
From the question we are told that
The height at which he let go of the brief case is h = 130 m
The time taken before the the brief case hits the water is t = 6 s
Generally the initial speed of the briefcase (Which also the speed of the helicopter )before the man let go of it is mathematically evaluated using kinematic equation as
Here s is the distance covered by the bag at sea level which is zero
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