Answer:
a and b.
Explanation:
In general types of wave
1. Transverse wave :
In these waves particle are vibrate perpendicular to motion of waves.
Ex : Electromagnetic wave , Radio wave .
2. Longitudinal wave :
In these waves particle are vibrate along the motion of waves.
Ex : Sound wave
Mechanical wave :
1 .These are transverse wave or Longitudinal wave or combination of them .
2.These waves required medium for propagation.
3. The particle are vibrate perpendicular to motion of waves.
So the option a and b are correct.
Answer:
5.72 seconds
848.27 m/s
97.94 m
Explanation:
t = Time taken
u = Initial velocity = 15 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²

Time taken to reach maximum height is 0.97 seconds

So, the stone would travel 11.47 m up
So, total height stone would fall is 75+11.47 = 86.47 m
Total distance travelled by the stone would be 75+11.47+11.47 = 97.94 m

Time taken by the stone to travel 86.47 m to the water is is 4.2 seconds
The stone reaches the water after 4.2+1.52 = 5.72 seconds after throwing the stone

Speed just before hitting the water is 848.27 m/s
Answer: 51841.5 Watts
Explanation: Using the kinematic equation for the final velocity for a constant acceleration we have:
Vf=Vi+a*t
replacing the values the results is
a=(Vf-Vi)/t= (30.55 m/s-19.44 m/s)/5s= 2.22 m/s^2
Remenber that to convert the speed in Km/h to m/s we have to multiplier by the factor 0.277.
Finally to calculate the increment of power get the final velocity we have to use Neton second law to determine the Force applied to the car.
F=m* a=2100 Kg* 2.22 m/s^2= 4666.2 N
Then increment power to accelerate is given by:
ΔPower= Force* Δ velocity= 4666.2 N* 11,11 m/s= 51841.5 Watts
~Formula: Voltage= current• resistance
(V= Ir)
~Using this formula, plug in the numbers from the equation into the formula
~5=25i
~Now you have a one-step equation
~Divide by 25 on both sides and you should get your answer:
~I= 0.2 (which means current is 0.2)
Answer:

Explanation:
Given:
Initial velocity of the vehicle, 
distance between the car and the tree, 
time taken to respond to the situation, 
acceleration of the car after braking, 
Using equation of motion:
..............(1)
where:
final velocity of the car when it hits the tree
initial velocity of the car when the tree falls
acceleration after the brakes are applied
distance between the tree and the car after the brakes are applied.

Now for this situation the eq. (1) becomes:
(negative sign is for the deceleration after the brake is applied to the car.)