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2 years ago

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A vertical spring with a spring constant value of 4500 N/m is compressed 60 cm. A 5.5 kg pumpkin is placed on the end of the spr

ing, and the spring is released. To the nearest whole number, the pumpkin will rise m. ?

2 answers:

MrMuchimi2 years ago

6 0

The answer is 15, I just took the Review.

borishaifa [10]2 years ago

3 0

15.0 m

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, all the energy of the system is stored in the elastic potential energy of the compressed spring, which is given by

$E=\frac{1}{2}kx^2=\frac{1}{2}(4500 N/m)(0.60 m)^2=810 J$

When the spring is released, the pumpkin of mass m=5.5 kg is pushed upwards. All the energy is then converted into gravitational potential energy of the pumpkin when it reaches its maximum height h:

$E=mgh$

Re-arranging the equation, we can find h:

$h=\frac{E}{mg}=\frac{810 J}{(5.5 kg)(9.8 m/s^2)}=15.0 m$

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A solid sphere of brass (bulk modulus of 14.0 ✕ 1010 N/m2) with a diameter of 2.20 m is thrown into the ocean. By how much does

astra-53 [7]

Answer:

Diameter decreases by the diameter of 0.0312 m.

Explanation:

Given that,

Bulk modulus = 14.0 × 10¹⁰ N/m²

Diameter d = 2.20 m

Depth = 2.40 km

Pressure = ρ g h = 1030 × 9.81 × 2.4 × 1000

= 24.25 × 10⁶ N/m²

Volume = $\dfrac{4}{3} \pi r^3$

$\dfrac{\Delta V}{V}=\dfrac{(\Delta r)^3}{r^3}$

Bulk modulus is equal to

$B = -\dfrac{\Delta P}{\dfrac{\Delta V}{V} }$

now

$B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{r^3} }$

$B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{1.1^3} }$

$(\Delta r)^3 = \dfrac{24.25 \times 10^6 \times 1.1^3}{14.0 \times 10^{10}}$

Δ r = -0.0156 m

change in diameter

Δ d = -2 × 0.0156

Δ d = -0.0312 m

Diameter decreases by the diameter of 0.0312 m.

7 0

1 year ago

If Pete ( mass=90.0kg) weights himself and finds that he weighs 30.0 pounds, how far away from the surface of the earth is he

shutvik [7]

Answer: 9938.8 km

Explanation:

1 pound-force = 4.48 N

30.0 pounds-force = 134.4 N

The force of gravitation between Earth and object on the surface of is given by:

$F = \frac{GMm}{R^2} = mg$

Where M is the mass of the Earth, m is the mass of the object, R (6371 km) is the radius of the Earth.

At height, h above the surface of the Earth, the weight of the object:

$(mg)'= \frac{GMm}{(R+h)^2}$

we need to find "h"

taking the ratio of two:

$\frac{mg}{(mg)'}=\frac{(R+h)^2}{R^2}\\ \Rightarrow \frac{90kg \times 9.8 m/s^2}{134.4 N}=\frac{(R+h)^2}{R^2}\\ \Rightarrow 6.56 R^2= (R+h)^2 \Rightarrow h= (2.56-1)R\\ \Rightarrow h = 1.56 R = 1.56 \times 6371 km = 9938. 8 km$

Hence, Pete would weigh 30 pounds at 9938.8 km above the surface of the Earth.

5 0

2 years ago

A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force?

Talja [164]

Answer:

1.05 N

Explanation:

K = 0.7 N/m

e = 1.5 m

F = ?

from Hooke's law of elasticity

F = Ke

= 0.7×1.5

= 1.05 N

5 0

1 year ago

A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

Svet_ta [14]

Answer:

The speed is $\sqrt{2}v_{0}$ .

(a) is correct option.

Explanation:

Given that,

Potential difference $V= V_{0}$

Speed $v = v_{o}$

If it were accelerated instead

Potential difference $V'=2V_{0}$

We need to calculate the speed

Using formula of initial work done on proton

$W = q V$

We know that,

$\Delta W=\Delta K.E$

$q V=\dfrac{1}{2}mv^2$

Put the value into the formula

$q V_{0}=\dfrac{1}{2}mv_{0}^2$

$v_{0}^2=\dfrac{2qV_{0}}{m}$ ....(I)

If it were accelerated instead through a potential difference of $2 V_{0}$ , then it would gain a speed will be given as :

Using an above formula,

$v_{0}'^2=\dfrac{2qV_{0}}{m}$

Put the value of $V_{0}$

$v_{0}'^2=\dfrac{2q\times2V_{0}}{m}$

$v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}$

$v_{0}'=\sqrt{2}v_{0}$

Hence, The speed is $\sqrt{2}v_{0}$ .

6 0

1 year ago

A recipe for candy requires that the liquid ingredients be stirred constantly until the liquid reaches a temperature of 140°C. W

lara31 [8.8K]

Sample Response: A wooden spoon will prevent the person’s hand from burning because wood is an insulator. An insulator slows the transfer of thermal energy so that very little thermal energy from the hot liquid will transfer to the person’s hand.

include:

-A wooden spoon will prevent the person’s hand from burning.

-Wood is an insulator.-An insulator slows the transfer of thermal energy.<span>-The wooden spoon will transfer very little thermal energy to the person’s hand.

you're welcome lol</span>

6 0

1 year ago

Read 2 more answers