Answer:
0.5 m/s2
Explanation:
Step 1:
Data obtained from the question.
Total Mass = 60Kg
Net force = 30N
Acceleration =?
Step 2
Determination of the acceleration.
Force = Mass x Acceleration.
With the above equation, we can easily obtain the acceleration as follow:
30 = 60 x Acceleration
Divide both side by 60
Acceleration = 30/60
Acceleration = 0.5 m/s2
Now, we can thus say that the acceleration at that moment is 0.5 m/s2
Ok, I think this is right but I am not sure:
Q = ϵ
0AE
A= π π
r^2
=(8.85x10^-12 C^2/Nm^2)
( π π (0.02m)^2)
(3x10^6 N/C) =3.3x10^-8 C = 33nC N = Q/e = (3.3x10^-8 C)/(1.60x10^-19 C/electron) = 2.1x10^11 electrons
Moon diameter - 2,160 miles Sun diameter - 864,000 miles
So, in terms of diameter the Sun is 400 times bigger then the Moon. If we divide 150,000,000 km by 384,000 km we get 390.625 almost the same number.
The Sun and the Moon have sizes which vary a small amount as seen from Earth.
The Sun appears largest about January 4th and smallest around July 4th.
Answer:
C
Explanation:
Q=mcΔθ
Q=quantity of heat , m= mass of the storage rock
Δθ= temperature change.
m= Q/(cΔθ)
Q=5.4
Δθ=62°C-20°C
=42°C
c=0.21cal/g.°C
m≈6100000g
m≈6100kg
Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.
If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.
