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artcher [175]
2 years ago
8

According to Newton's Law of Universal Gravitation, which of the following would cause the attractive force between a planet and

the Sun to be doubled?
A. Doubling the mass of the planet
B. Quadrupling the distance from the sun
C. Doubling the distance from the sun
D. Squaring the mass of the planet oxford
Physics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

it is either a or c

Explanation:

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A squirrel in a tree drops an acorn. how long does it take the acorn to fall 20 feet?
mart [117]

We use the equation of motion,

S= ut+\frac{1}{2}at^{2}

Here, S is the height, u is initial velocity and a is acceleration.

Given, S = 20 \ ft S = 20 \ ft = 20 \times\frac{1 \ m}{3.2808399 ft}  = 6.096 \ m

As  acorn falls from tree, therefore we take the value of a = 9.8 \ m/s^2 and initial velocity u = 0.

Substituting these values in equation of motion,

6.096 \ m = 0 \times t +\frac{1}{2} \times 9.8 m/s^2 (t)^2 \\\\\ t = 1.12 \ s

Thus, the time taken by the acorn to fall 20  feet ( 6.096 m ) is 1.12 s.

5 0
2 years ago
Question
Jobisdone [24]

Answer:

A wavelength is a measure of distance between two consecutive crests or trough. So , the unit of wavelength is same as unit of distance. I.e metre

7 0
2 years ago
A physics student shoves a 0.50-kg block from the bottom of a frictionless 30.0° inclined plane. The student performs 4.0 j of w
Musya8 [376]

Answer:1.63 m

Explanation:

Given

mass of block m=0.5 kg

inclination \theta =30^{\circ}

Amount of work done W=4 J

block slides a distance s along the Plane

Work done =change in Potential Energy

Increase in height of block is s\sin \theta

Change in Potential Energy =mg(\sin \theta -0)

\Delta P.E.=0.5\times 9.8\times s\sin 30

4=0.5\times 9.8\times s\sin 30

s=\frac{4}{2.45}      

s=1.63 m

5 0
2 years ago
In which atmosphere layer does 80 percent of the gas in the atmosphere<br> reside?
VladimirAG [237]

Answer: TheTroposphere contains 80% of the total gas in the atmosphere

7 0
2 years ago
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If you are driving 72 km/h along a straight road and you look to the side for 4.0 s, how far do you travel during this inattenti
Ann [662]
We know that speed equals distance between time. Therefore to find the distance we have that d = V * t. Substituting the values d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km.Therefore during this inattentive period traveled a distance of 0.08Km
8 0
2 years ago
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