Answer:
ball clears the net
Explanation:
= initial speed of launch of the ball = 20 ms^{-1}
= angle of launch = 5 deg
Consider the motion of the ball along the horizontal direction
= initial velocity = 
= time of travel
= horizontal displacement of the ball to reach the net = 7 m
Since there is no acceleration along the horizontal direction, we have
Eq-1
Consider the motion of the ball along the vertical direction
= initial velocity = 
= time of travel
= Initial position of the ball at the time of launch = 2 m
= Final position of the ball at time "t"
= acceleration in down direction = - 9.8 ms⁻²
Along the vertical direction , position at any time is given as

Since Y > 1 m
hence the ball clears the net
Hublle Space Telescope
- Orbits around Earth.
- Receive light before it enters Earth's Atmosphere.
- Get information about stars before they are born.
Alma Radio Telescope
- Installed on land.
- Receive light after it passes through Earth's Atmosphere.
- Get information about stars after they are born.
Aluminium, or heavier version copper.
The technique used is most likely Bandwagon.
So, B.
Answer: option <span>A) a train moving north of east at an angle of 25°
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Explanation:
1) You need to choose your axis. In this case North is vertical and positive, South is vertical and negative, East is horizontal and positive, and West is horizontal and negative.
2) The vector with the two positive components is a vector in the first quadrant (North and East). That is what North of East 25° means.
3) Regarding the other options:
<span>B) a bus moving North of East at an angle of 95°: since the angle is greater tnan 90° the vector is in the second quadrant: its horizontal component is negative.
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C) a boat moving South of West at an angle of 40°: this is in the third quadrant: the two components are negative.</span>
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D) a car moving south of west at an angle of 10°: as in the option C), this is in the third quadrant: the two components are negative.
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