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Ne4ueva [31]
2 years ago
7

The drawing shows a side view of a swimming pool. The pressure at the surface of the water is atmospheric pressure. The pressure

at the bottom of the pool is greater because of the weight of water above it. As a storm approaches, the atmospheric pressure drops. What happens to the pressure at the bottom of the pool? A The pressure at the bottom of the pool decreases by exactly the same amount as the atmospheric pressure decreases. B Nothing happens to the pressure at the bottom of the pool. C The pressure at the bottom of the pool increases. D The pressure at the bottom of the pool decreases, but not as much as the atmospheric pressure decreases.
Physics
2 answers:
Nikitich [7]2 years ago
7 0

Answer:

A) To true. he pressure at the bottom of the pool decreases by exactly the same amount as the atmospheric pressure decreases

Explanation:

Let us propose the solution of this problem before seeing the final statements. The pressure increases with the depth of raposin due to the weight of water that is above the person and also the pressure exerted by the atmosphere on the entire pool, the equation describing this process is

    P =P_{atm} + ρ g y

Where P_{atm} is the atmospheric pressure, ρ  the water density, and 'y' the depth measured from the surface.

Let's examine this equation in we see that the total pressure is directly proportional to the atmospheric pressure and depth

Now we can examine the claims

A) To true. State agreement or with the equation above

B) False. Pressure changes with atmospheric pressure

C) False. It's the opposite

D) False. They are directly proportional

miss Akunina [59]2 years ago
3 0

A The pressure at the bottom of the pool decreases by exactly the same amount as the atmospheric pressure decreases

<h3>Further explanation </h3>

Hydrostatic pressure is pressure caused by the weight of a liquid.

The weight of a liquid is affected by the force of gravity.

If a liquid is placed in a container, the higher the liquid content in the container, the heavier the liquid content is and the greater the liquid pressure at the bottom of the container.

The hydrostatic pressure of a liquid can be formulated:

\large{\boxed{\bold {P_h ~ = ~ \rho.g.h}}

Ph = hydrostatic pressure (N / m², Pa)

ρ = density of liquid (kg / m³)

g = acceleration due to gravity (m / s²)

h = height / depth of liquid surface (m)

If the container is open, then the atmospheric pressure (P₀) can be entered into the equation.

\large{\boxed {\bold {P_h ~ = ~ P_o ~ + ~ \rho.g.h}}

The magnitude of P₀ is usually equal to = 1.01.10⁵ Pascal (Pa = N / m²) = 1 atm

For example submarines  :

The deeper a submarine is, the greater the hydrostatic pressure it experiences, so that the hull / wall of the submarine is made thick to withstand that pressure.

As a storm approaches, the atmospheric pressure drops

Because the hydrostatic pressure is proportional to the atmospheric pressure, the pressure at the bottom of the pool will also be reduced

<h3>Learn more </h3>

Isaac Newton's investigations of gravity

brainly.com/question/1747622

Gravitational force

brainly.com/question/7955425

increase the gravitational force between two objects

brainly.com/question/2306824

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Due to the definition of cross product, the magnitude of the torque is given by:

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Where \theta is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when sin\theta is equal to one, solving for r:

r=\frac{\tau}{F}\\r=\frac{55\frac{N}{m}}{135N}\\r=0.41m

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A proton of mass mp is released from rest just above the lower plate and reaches the top plate with speed vp. An electron of mas
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Answer:

v_e=\sqrt{\frac{m_pv_p^2}{m_e}}

Explanation:

You can consider that the force that acts over the proton is the same to the force over the electron. This is because the electric force is given by:

F=qE

F_p=F_e

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by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:

m_pa_p=qE\\\\a_p=\frac{v_p^2}{2d}\\\\\frac{m_pv_p^2}{2d}=qE

(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.

By doing the same for the electron you obtain:

\frac{m_ev_e^2}{2d}=qE

we can equals these expressions for both proton and electron, because the forces qE are the same:

\frac{m_pv_p^2}{2d}=\frac{m_ev_e^2}{2d}\\\\v_e=\sqrt{\frac{m_pv_p^2}{m_e}}

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A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate
diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

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Where,

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On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

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According to the data given we have to,

Q_{source} = 200000Btu

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Answer:

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From the equation, the electric potential energy is directly proportional to the charge q.

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From the equation, the electric potential energy is inversely proportional to the distance of separation r.

If the distance is doubled, U is divided by 2. This means that the electric potential energy is multiplied by 1/2.

Effect on potential difference

Potential difference is defined as the change in electric potential energy.

Increase in the charge causes an increase in the potential difference and an increase in the distance of separation decreases the potential difference.

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