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swat32
2 years ago
5

A finite rod of length L has total charge q, distributed uniformly along its length. The rod lies on the x -axis and is centered

at the origin. Thus one endpoint is located at (−L/2,0), and the other is located at (L/2,0). Define the electric potential to be zero at an infinite distance away from the rod. Throughout this problem, you may use the constant k in place of the expression 14πϵ0.
Physics
1 answer:
Harlamova29_29 [7]2 years ago
4 0

Answer:

the electric potential at an infinite distance is the workdone in moving a charge from one point at an infinite distance to another point at an infinite distance. This will be zero.

Explanation:

Electric potential is given by

E= kQ/r²

If r becomes   ∞, then

E= kQ/(∞)²= 0

So electric potential at an infinite distance away from the rod is zero

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Calcium chloride is used to make pickles. The calcium atom transfers electrons to chlorine atoms, leading to the formation of ch
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Calcium chloride contains ionic bonds.

Pennies contain metallic bonds.

Hydrochloric acid contains covalent bonds.



You're welcome.

3 0
2 years ago
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Consider four different oscillating systems, indexed using i = 1 , 2 , 3 , 4 . Each system consists of a block of mass mi moving
Rzqust [24]

Answer:

The order is 2>4>3>1 (TE)

Explanation:

Look up attached file

4 0
2 years ago
8. Rubbing a plastic bag and a balloon with a cloth gives both objects a net negative charge. The balloon's
Dafna1 [17]

Answer:

0.214 m

Explanation:

In order for the bag to levitate and not fall down, the electrostatic force between the bag and the balloon must balance the weight of the bag.

Therefore, we can write:

k\frac{q_1 q_2}{r^2}=mg

where

k is the Coulomb constant

q_1=-1\cdot 10^{-10}C is the charge on the balloon

q_2=-1\cdot 10^{-5} C is the charge on the bag

r is the separation betwen the bag and the balloon

m=0.02 g=2\cdot 10^{-5} kg is the mass of the bag

g=9.8 m/s^2 is the acceleration due to gravity

Solving for r, we find the distance at which the bag must be held:

r=\sqrt{\frac{kq_1 q_2}{mg}}=\sqrt{\frac{(9\cdot 10^9)(-1\cdot 10^{-10})(-1\cdot 10^{-5})}{(2\cdot 10^{-5})(9.8)}}=0.214 m

5 0
2 years ago
During fabrication processes, polymeric materials are generally subjected to which of the following conditions? The ambient temp
geniusboy [140]

Answer:

- Elevated temperatures.

- Elevated pressures.

Explanation:

In the manufacture of plastic products are used:

Raw material (pellets) which are the monomers that promote the chemical reaction.

To these are added the charges, in order to reduce the cost of the final product and improve some properties. These charges can be fiberglass, paper, metal structures.

Additives are also added whose mission is to improve or achieve certain properties, such as reducing friction, reducing chemical degradation, increasing electrical conductivity, coloring the product, and all this happens in the presence of a catalyst that is responsible for initiating and accelerating the chemical reaction process.

There are different methods of production of plastics, one of the most frequent is by injection.

Injection is a process that is carried out on machines similar to extrusion machines, in which the spindle, in addition to rotating, has an axial displacement.

In the injection, once the mold is filled, it is separated from the nozzle of the machine, breaking the feed channel. After a certain time, the piece already cooled is demoulded.

High pressures and temperatures are necessary, but parts of good finish and at high production speeds are obtained

3 0
2 years ago
Approximately 1.000 g each of four gasses H2, Ne, Ar, and Kr are placed in a sealed container all under1.5 atm of pressure. Assu
Vera_Pavlovna [14]

Answer:

The partial pressure of H2 is 0.375 atm

The partial pressure of Ne is also 0.375 atm

Explanation:

Mass of H2 = 1 g

Mass of Ne = 1 g

Mass of Ar = 1 g

Mass of Kr = 1 g

Total mass of gas mixture = 1 + 1 + 1 + 1 = 4 g

Pressure of sealed container = 1.5 atm

Partial pressure of H2 = (mass of H2/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm

Partial pressure of Ne = (mass of Ne/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm

7 0
2 years ago
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