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yan [13]
2 years ago
10

Derive an algebraic equation for the vertical force that the bench exerts on the book at the lowest point of the circular path i

n terms of the book’s mass mb, tangential speed vb, radius R of the path, and physical constants, as appropriate. Do not substitute any numerical values for variables or physical constants.

Physics
1 answer:
fiasKO [112]2 years ago
4 0

Answer:

The algebraic equation is:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

Explanation:

Given information:

mb = book's mass

vb = tangential speed

R = radius of the path

Question: Derive an algebraic equation for the vertical force, Fv = ?

To derive the equation, we need to draw a force diagram for this case, please, see the attached diagram. As you can see, there are three types of forces acting on the system. Two up and one of the weight acting down. Therefore, the algebraic equation is as follows:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

The variables were defined above and g is the gravity.

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OLEGan [10]

Answer:

Let us consider the case of a bus turning around a corner with a constant velocity, as the bus approaches the corner, the velocity at say point A is Va, and is tangential to the curve with direction pointing away from the curve. Also, the velocity at another point say point B is Vb and is also tangential to the curve with direction pointing away from the curve.<em> </em><em>Although the velocity at point A and the velocity at point B have the same magnitude, their directions are different (velocity is a vector quantity), and hence we have a change in velocity. By definition, an acceleration occurs when we have a change in velocity, so the bus experiences an acceleration at the corner whose direction is away from the center of the corner</em>.

The acceleration is not aligned with the direction of travel because<em> the change in velocity is at a tangent (directed away) to the direction of travel of the bus.</em>

4 0
2 years ago
A stone is thrown into a pond. Five waves were made from the same source in 10 seconds.
lina2011 [118]

Answer:

The Frequency of the wave is 0.2Hertz

The period is 2seconds

Explanation:

We are asked to find the frequency and period

Frequency is the number of oscillations completed in one seconds

If five waves were made from the same source in 10 seconds, hence;

Frequency = number of oscillation/Time

Frequency = 5/10

Frequency = 0.5Hertz

Next is to get the period

Period = 1/Frequency

Period = 1/0.5

Period = 2seconds

3 0
2 years ago
Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their p
worty [1.4K]

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

  • U1/U2=6
  • U1/U2=6

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy  is mathematically given as

U=\frac{-k*qQ}{r}

Therefore

The Equations of U1 and U2 is

For U1

U1=\frac{-k*q_1Q}{r}

For U2

U2=\frac{-k*q_1Q}{3*2r}

Since

U is a function of q and  q2=q1/3

Therefore

U1/U2=6

For Question 2

For U1

U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}

Therefore

U1/U2=6

For more information on this visit

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7 0
2 years ago
Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal,
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Answer: yes.

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It depends on 3 factors:

1. The temperature

2. The specific heat capacity of the metal

3. The thermal conductivity of the metal.

The metal getting warmer also depend on the reflection and the absorption of light energy in which it will surely absorb some energy and not reflect all.

When visible light is absorbed by an object, the object converts the short wavelength light into long wavelength heat. This causes the object to get warmer. 

6 0
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A planet of mass M and radius R has no atmosphere. The escape velocity at its surface is ve. An object of mass m is at rest a di
zubka84 [21]

Answer:

Explanation:

Expression for escape velocity

ve = \sqrt{\frac{2GM}{R} }

ve² R / 2 = GM

M is mass of the planet , R is radius of the planet .

At distance r >> R , potential energy of object

= \frac{-GMm}{r}

Since the object is at rest at that point , kinetic energy  will be zero .

Total mechanical energy  = \frac{-GMm}{r} + 0 = \frac{-GMm}{r}

Putting the value of GM = ve² R / 2

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This mechanical energy will be conserved while falling down on the earth due to law of conservation of mechanical energy  . So at surface of the earth , total mechanical energy

=  ve² Rm / 2 r

8 0
2 years ago
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