All categories

2 years ago

A moving 46.6 kg sled feels a 52.9 N friction force. what is the coefficient of friction

Physics

2 answers:

Leni [432]2 years ago

7 0

Answer:

The coefficient of friction of the sled is 0.115

Explanation:

It is given that,

Mass of the sled, m = 46.6 kg

Frictional force acting on it, F = 52.9 N

We need to find the coefficient of friction. Frictional force is given by :

$F=\mu mg$

$\mu=\dfrac{F}{mg}$

$\mu=\dfrac{52.9\ N}{46.6\ kg\times 9.8\ m/s^2}$

$\mu = 0.115$

So, the coefficient of friction of the sled is 0.115. Hence, this is the required solution.

Setler [38]2 years ago

4 0

Answer:

F=UR

52.9=U*46.6

U=52.9/46.6

U=1.135

You might be interested in

A Honda Civic and an 18 wheeler approach a right angle intersection and then collide. After the collision, they become interlock

Goryan [66]

Answer:

The concept of conservation of momentum is applied in the particular case of collisions.

The general equation ig given by,

$M_1V_1 + M_2V_2 = (M_1+M_2) * V_f,$

Where,

$M_2 = 4 M_1$

The crash occurs at an intersection so we must separate the two speeds by their respective vector: x, y.

In the case of the X axis, we have that the body $M_2$ has a speed = 0, this because it is not the direction in which it travels, therefore

$M_1* 13 = (M_1+M_2) * V_{fx} \\M_1*13 = (M_1+4M_1)*V_{fx}\\M_1*13=5M_1*V_{fx}\\Vx = \frac{13}{5}m/s$

The same analysis must be given for the particular case in the Y direction, where the mass body $M_1$ does not act with its velocity here, therefore:

$M_2* 13 = (M_1+M_2) * V_{fy},\\4*M_1* 13 = 5Ma * V_{fy} ,\\V_{fy} = \frac{52}{5}m/s ,$

We have the two components of a velocity vector given by $V_f = \frac{13}{5}\hat{i} + \frac{52}{5}\hat{j}$

Get the magnitude,

$V_f = \sqrt{(\frac{13}{5})^2+(\frac{52}{5})^2}$

$V_f = 10.72 m/s$

With a direction given by

$Tan^{-1} \frac{4}{1} = 75.96 \°$

8 0

2 years ago

A flying mosquito hits the windshield of a moving car and gets smashed, but the car is intact. Which of the following statements

zhannawk [14.2K]

Answer:

Action and reaction are the same

Explanation:

Let us carefully analyze the situation in the context of Newton's third law, when the car hits the mosquito exerts a force that acts on the mosquito, ACTION and the mosquito responds to the force that is being applied with a force of equal magnitude and direction or opposite applied to the car (Reaction).

Consequently, the correct answer is: The force of the car on the mosquito is of the same magnitude as that of the mosquito on the car

6 0

2 years ago

A sample of nitrogen gas exerts a pressure of 9.80 atm at 32 C. What would its temperature be (in C) when its pressure is increa

Harlamova29_29 [7]

Answer:

T₂ = 111.57 °C

Explanation:

Given that

Initial pressure P₁ = 9.8 atm

T₁ = 32°C = 273 + 32 =305 K

The final pressure P₂ = 11.2 atm