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2 years ago

A moving 46.6 kg sled feels a 52.9 N friction force. what is the coefficient of friction

Physics

2 answers:

Leni [432]2 years ago

7 0

Answer:

The coefficient of friction of the sled is 0.115

Explanation:

It is given that,

Mass of the sled, m = 46.6 kg

Frictional force acting on it, F = 52.9 N

We need to find the coefficient of friction. Frictional force is given by :

$F=\mu mg$

$\mu=\dfrac{F}{mg}$

$\mu=\dfrac{52.9\ N}{46.6\ kg\times 9.8\ m/s^2}$

$\mu = 0.115$

So, the coefficient of friction of the sled is 0.115. Hence, this is the required solution.

Setler [38]2 years ago

4 0

Answer:

F=UR

52.9=U*46.6

U=52.9/46.6

U=1.135

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2 years ago

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2 years ago

Read 2 more answers

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2 years ago

A steel tank of weight 600 lb is to be accelerated straight upward at a rate of 1.5 ft/sec2. Knowing the magnitude of the force

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Answer:

a) the values of the angle α is 45.5°

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Applying the free equilibrium equation along x-direction

from the diagram

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2 years ago