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2 years ago

A moving 46.6 kg sled feels a 52.9 N friction force. what is the coefficient of friction

Physics

2 answers:

Leni [432]2 years ago

7 0

Answer:

The coefficient of friction of the sled is 0.115

Explanation:

It is given that,

Mass of the sled, m = 46.6 kg

Frictional force acting on it, F = 52.9 N

We need to find the coefficient of friction. Frictional force is given by :

$F=\mu mg$

$\mu=\dfrac{F}{mg}$

$\mu=\dfrac{52.9\ N}{46.6\ kg\times 9.8\ m/s^2}$

$\mu = 0.115$

So, the coefficient of friction of the sled is 0.115. Hence, this is the required solution.

Setler [38]2 years ago

4 0

Answer:

F=UR

52.9=U*46.6

U=52.9/46.6

U=1.135

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cluponka [151]

Answer:

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Explanation:

This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition

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cos 45 = x₁ / V₁

sin 45 = y₁ / V₁

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Unknown 3 vector

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x₃ = -18.38 km

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y₃ = 70 -18.38 - 45

y₃ = 6.62 km

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v₃ = (-18.38 i ^ +6.62 j^ ) km

let's use the Pythagorean theorem to find the length

v₃ = √ (18.38² + 6.62²)

v₃ = 19.54 km

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tan θ = y₃ / x₃

θ = tan⁻¹ (y₃ / x₃)

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I mean the address is

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2 years ago

A 0.305 kg book rests at an angle against one side of a bookshelf. The magnitude and direction of the total force exerted on the

tankabanditka [31]

Answer

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$\theta_L= 31^0$

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$F_L cos {\theta_L} + F_b sin {\theta_b} = m g$

$1.52 times cos {31^0} + F_b sin {\theta_b} = 0.305 \times 9.8$

$F_b sin {\theta_b} = 2.989 -1.303$

$F_b sin {\theta_b} = 1.686$

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$F_b cos {\theta_b} = F_L sin {\theta_L}$

$cos {\theta_b} = \dfrac{F_L sin {\theta_L}}{F_b}$

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2 years ago

There is a distinction between average speed and the magnitude of average velocity. Give an example that illustrates the differe

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Let's start by reminding the definition of the two quantities:

- Speed is a scalar quantity that tells "how fast" an object is moving, regardless of its direction of motion.

Speed can be calculate as:

$speed = \frac{d}{t}$

where:

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- Velocity is instead a vector quantity, given by:

$velocity = \frac{d}{t}$

where;

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t is the time taken

Since it is a vector, velocity has both a magnitude and a direction, therefore it also takes into account the direction of motion of the object.

For an object in motion in a straight line, speed and velocity are the same. However, this is not always the case.

In fact, an example of motion in which the two quantities are different is the circular motion. Consider for example the object making one complete revolution along the circle. Therefore, its average speed is the ratio between the length of the perimeter (the distance) divided by the time taken:

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