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KiRa [710]
2 years ago
14

A train composed of a small engine car and a massive cargo car are connected as they move along a track. The speed of the small

engine car is ____(blank 1)___ the speed of the massive cargo car. The magnitude of the acceleration of the small engine car is ____(blank 2)___ the magnitude of the acceleration of the massive cargo car because ____(blank 3)___ .
Physics
1 answer:
stepan [7]2 years ago
7 0

Answer:

The speed of the small engine car is <u>_equal to_</u> the speed of the massive cargo car. The magnitude of the acceleration of the small engine car is <u>_equal to_</u> the magnitude of the acceleration of the massive cargo car because <u>_the cars speeds cannot change by different amounts_</u> .

Explanation:

The two cars are connected, hence, they move with the same speed at all points in time.

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Determine whether each substance will sink or float in corn syrup, which has a density of 1.36 g/cm3. Write “sink” or “float” in
Tatiana [17]

Explanation:

  • A substance will floats if it is having lower density than the density of the liquid in which it is placed.
  • A substance will sink if it is having density greater than the density of the liquid in which it is kept.

Density of corn syrup = 1.36 g/cm^3

1) Density of gasoline = 0.748 g/cm^3

Density of the gasoline is less than the the density of corn syrup which means it will float in corn syrup.

2) Density of water = 1 g/cm^3

Density of the water is less than the the density of corn syrup which means it will float in corn syrup.

3) Density of honey = 1.45 g/cm^3

Density of the gasoline is more than the the density of corn syrup which means it will sink in corn syrup.

4) Density of titanium = 4.506 g/cm^3

Density of the titanium is more than the the density of corn syrup which means it will sink in corn syrup.

3 0
2 years ago
Read 2 more answers
A squirrel in a tree drops an acorn. how long does it take the acorn to fall 20 feet?
mart [117]

We use the equation of motion,

S= ut+\frac{1}{2}at^{2}

Here, S is the height, u is initial velocity and a is acceleration.

Given, S = 20 \ ft S = 20 \ ft = 20 \times\frac{1 \ m}{3.2808399 ft}  = 6.096 \ m

As  acorn falls from tree, therefore we take the value of a = 9.8 \ m/s^2 and initial velocity u = 0.

Substituting these values in equation of motion,

6.096 \ m = 0 \times t +\frac{1}{2} \times 9.8 m/s^2 (t)^2 \\\\\ t = 1.12 \ s

Thus, the time taken by the acorn to fall 20  feet ( 6.096 m ) is 1.12 s.

5 0
2 years ago
A string is wrapped around a pulley with a radius of 2.0 cm and no appreciable friction in its axle. The pulley is initially not
stiks02 [169]

Answer:

2

Explanation:

2

5 0
2 years ago
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A camera gives a proper exposure when set to a shutter speed of 1/250 s at f-number F8.0. The photographer wants to change the s
Oksana_A [137]

Answer:

F4.0

Explanation:

To obtain a shutter speed of 1/1000 s to avoid any blur motion the f-number should be changed to F4.0 because the light intensity goes up by a factor of 2 when the f-number is decreased by the square root of 2.

5 0
2 years ago
A certain satellite travels in an approximately circular orbit of radius 2.0 × 106 m with a period of 7 h 11 min. Calculate the
kap26 [50]

Answer: Mass of the planet, M= 8.53 x 10^8kg

Explanation:

Given Radius = 2.0 x 106m

Period T = 7h 11m

Using the third law of kepler's equation which states that the square of the orbital period of any planet is proportional to the cube of the semi-major axis of its orbit.

This is represented by the equation

T^2 = ( 4π^2/GM) R^3

Where T is the period in seconds

T = (7h x 60m + 11m)(60 sec)

= 25860 sec

G represents the gravitational constant

= 6.6 x 10^-11 N.m^2/kg^2 and M is the mass of the planet

Making M the subject of the formula,

M = (4π^2/G)*R^3/T^2

M = (4π^2/ 6.6 x10^-11)*(2×106m)^3(25860s)^2

Therefore Mass of the planet, M= 8.53 x 10^8kg

5 0
2 years ago
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