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velikii [3]
1 year ago
12

You are driving on the highway, and you come to a steep downhill section. As you roll down the hill, you take your foot off the

gas pedal. You can ignore friction, but you can't ignore air resistance.
Identify all the forces acting on the car.
Physics
2 answers:
NISA [10]1 year ago
6 0

Answer:

Explanation: Here you know that:

The car is in downhill (so the gravitational force accelerates the car downhill)

we can ignore the friction (so there is no force of friction)

We can not ignore the air resistance (so whe have force of air resistance that is oposite to the direction in which the car moves)

You take the foot of the gas pedal (so there is no intrinsic acceleration of the car)

then the only two forces are the component of the gravitational force in the downhill direction, and the force of the air resistance that is in opposite direction than the gravitational force.

Natasha2012 [34]1 year ago
5 0

Answer:

air

Explanation:

The car is being slowed down by air.

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Describe the energy transformations that take place when a skier starts skiing down a hill but after a time is brought to rest b
Andrews [41]
<span>The skier will transform their gravitational energy into mostly kinetic energy (with a minor amount transformed into heat from the friction of the skis across the snow and air friction). Once the skier hits the snowdrift, their kinetic energy is transferred into the snow which moves when they strike it due to the kinetic energy that is now in the snow. Along with again a minor amount of heat energy transferred as they move through the snowdrift.</span>
6 0
2 years ago
Based on the emf value measured at frame 700, what is the average magnitude of the magnetic field inside the magnet assembly? No
Nadusha1986 [10]

Answer:

The average magnitude of magnetic field B= 0.0433/ d Tesla

(You have not provided length of side of loop, so if you divide this value by length you will get value of magnetic field.)

Explanation:

Induced emf

where B= magnetic field  

d= breadth of rectangular piece

V= velocity with which the rectangular piece = o.o6m/s

n= no of turns  = 10

EMF = 26mV

since d (breadth of the frame) is not given, I will use it as a variable

EMF= n×B×d×V ------------------(1) (EMF induced due to multiple turns)

From eq 1, we get

B= (EMF)/(n d V)

B= (26 X 0.001) / (10 d 0.06)

B= 0.0433/ d Tesla

4 0
1 year ago
For a Physics course containing 10 students, the maximum point total for the quarter was 200. The point totals for the 10 studen
Talja [164]

Answer:

130.5

Explanation:

According to the stemplot attached (Which I think it is, and if not, then you only need to replace the procedure with your data and you should be fine), you need to calculate first the points of all ten students. In that plot, we can easily calculate the points.

The first number in the colum represents the centen of the point, while the numbers of the second column, represents the units of that centen, for example if you see:

16 | 8 5 6

This means that the point for the students are 168, 165 and 166. Three students, three points.

If you watch the stemplot, the points for the students are:

116, 118, 121, 124, 128, 133, 137, 142, 146 and 179.

The median can be calculated using the mean between the two values in the middle of the sequence.

In this case, half of ten is 5, so, the numbers from the middle in this sequence are 128 and 133, therefore:

Median = 128 + 133 / 2 = 130.5

5 0
2 years ago
80 foot-pounds of work is needed to move the sofa in Tyler's apartment. Which of the following statements is true?
erastova [34]
D is the correct answer
hop it helped.
3 0
2 years ago
A cube with edges exactly 2 cm long is made of material with a bulk modulus of 3.5 x 109 n/m2. when it is subjected to a pressur
Igoryamba

As we know by the formula of bulk modulus

B = \frac{\Delta P}{-\Delta V/V}

now we can rearrange it as

\Delta V/V = -\frac{\Delta P}{B}

V_f - V = -V\frac{\Delta P}{B}

now the final volume after pressure is applied is given as

V_f = V(1 - \frac{\Delta P}{B})

now we know that

\Delta P = 3 \times 10^5 Pa

V = 2^3 cm^3 = 8 cm^3

B = 3.5 \times 10^9 N/m^2

now plug in all data

V_f = 8(1 - \frac{3 \times 10^5}{3.5 \times 10^9})

V_f = 7.999 cm^3

so volume is above after pressure is applied over it

5 0
2 years ago
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